mee no no nothing oops sorry
Answer:
f(x) = 1/25x² - 1
Step-by-step explanation:
Given that:
The quadratic function f(x) = y = ax² + bx + c
Replace (x,y) = (5,0)
0 = a5² + b5 + c
0 = 25a + 5b + c ---- (1)
The differential eqaution;dt/dx = 2ax + b at (x,y) = (0, -1) it has minimum.
Thus, dy/dx = 0
2ax + b = 0
2a(0) + b = 0
0 + b = 0
b = 0 --- (2)
Now, replace (x,y) = (0, - 1) into equation (1)
Then;
-1 = 0 + 0 + c
c = -1
From equation (1)
0 = 25a + 5(b) + c
0 = 25a + 5(0) + c
c = - 25a
a = - c/25
a = -(-1)/25
a = 1/25
Therefore; the derived quadratic equation:
y = ax² + bx + c
y = 1/25x² + (0)(x) - 1
y = 1/25x² - 1
f(x) = 1/25x² - 1
C = pi * d
452.16 = 3.14 * d
Divide both sides by 3.14
144 = d
Answer:
c*2=a2+b*2
c*2=3*2+6*2
c*2=9+36
c=root of 45
root of 45*8(sincethere are 8 sides if roots of45