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Anna11 [10]
3 years ago
7

What is −1 2/3⋅(−5 1/4) ? −8 3/4 −5 1/6 5 1/6 8 3/4

Mathematics
1 answer:
sammy [17]3 years ago
8 0
8 3/4 (8.75) is the answer.
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Brainliest and 30 points please help
kolbaska11 [484]

Answer:

22. Perimeter = 52 units

     Area = 160 Square Units

23. Notation form :  2 \times 10^{5}

     Standard Form : 200000

Step-by-step explanation:

22.

The formula for perimeter is

P = 2 (length + Width )

  = 2 ( 2x+3x+1)

  =  2(5x+1)

The Formula for Area of a rectangle is

A= length x width

A= 2x \times (3x+1)

A=6x^2+2x

Now we have to find the Perimeter and Area for x = 5

P = 2(5 x 5 +1)

P= 2(26)

P=52 units

A= 6 x 5 x 5 + 2 x 5

A= 150 + 10

A= 160 square units

23.

A. By using rule of exponents , we can determine that both the results will be same.

B.

Miriam's calculation

\frac{2.8 \times 10^{9}}{1.4 \times 10^{4}}

\frac{2.8}{1.4} \times 10^{9-4}

2 \times 10^5

Priya's calculation

\frac{2.8 \times 10^{2}}{1.4 \times 10^{-3}}

\frac{2.8}{1.4} \times 10^{2-(-3)}

2 \times 10^5

Standard notation

2 \times 10^5 = 200000

4 0
3 years ago
The following graph shows a proportional relationship.
Nina [5.8K]

Answer:

1.5

Step-by-step explanation:

k=\frac{y}{x}\\\\k=\frac{6}{4}\\\\k=1.5

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3 years ago
3(4-2x)=-2x<br> will make brainiest to the first two people that answer correctly with explanation
ASHA 777 [7]

Answer:

x = 3

Step-by-step explanation:

First, distribute 3 into the parenthesis:

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12 - 6x = -2x

Next, combine your x variables by adding +6x to both side:

12 - 6x = -2x           (-6x and +6x cancel out)

   +6x    +6x

12 = 4x                     (divide 12 by 4 to get x by itself)

/4     /4

x = 3

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3 years ago
Pls help 100 point <br>i really need help​
Umnica [9.8K]

Answer:

ASA - Angle Side Angle, it creates two separate triangles that face each other in which makes it identified as an Angle Side Angle.

(Picture Placed Below)

Step-by-step explanation:

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3 years ago
In an 80/20 mortgage, what is the first mortgage used for?
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Answer:

i think its letter B. 20% down payment

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