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3 years ago

Find tan2θ if θ terminates in Quadrant IV and cosθ =3/5 .

Mathematics

1 answer:

Liula [17]3 years ago

6 0

Answer:

The answer to your question is $\frac{-8}{3}$

Step-by-step explanation:

Data

cos Ф = 3/5

tan2Ф = ?

Quadrant IV

Process

1.- Remember that tanФ = $\frac{Opposite side}{Adjacent side}$ and cos Ф = $\frac{adjacent side}{hypotenuse}$

then, adjacent side = 3 and hypotenuse = 5

2.- Calculate opposite side

O² = h² - a²

O² = 5² - 3²

O² = 25 - 9

O² = 16

O = 4

3.- Calculate the tan 2Ф

tan 2Ф = 2( $\frac{-4}{3}$ ) The opposite side is negative in the fourth

quadrangle

tan 2Ф = $\frac{-8}{3}$

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Answer:

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Step-by-step explanation:

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3 years ago

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ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

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Also;

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