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weeeeeb [17]
3 years ago
11

A projectile is launched from ground level with an initial velocity of v0 feet per second. It's height in feet t seconds after l

aunch is given by s= -16t^2+v0t. Find the time the projectile will reach a height of 128ft when v0= 96 ft per second
Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

2345

Step-by-step explanation:

jyugtyg ytftrv g6bgy

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Y = 2x + 3<br> y = -3x + 3
AnnyKZ [126]

Answer:

y = -1

Step-by-step explanation:

hopefully it helped

5 0
3 years ago
8.4^3×4.8^2=<br>can you pleas help​
ira [324]

Answer:

13655.90016

Step-by-step explanation:

8.4^3 \times 4.8^2 \\= 592.704 \times 23.04\\=13655.90016

3 0
4 years ago
Write the equation in standard form for the circle with center (0, -6) and radius 7.
LUCKY_DIMON [66]

Step-by-step explanation:

the equation of circle is given by

(x - h) {}^{2} + (y - k) {}^{2}  =  {r}^{2}  \\ (x - 0) {}^{2}  +  {(y + 6)}^{2}  =  {7}^{2}  \\  {x }^{2}  +  {y}^{2}  + 12y + 36 = 49 \\  {x  }^{2}  +  {y}^{2}  + 12y = 13

4 0
2 years ago
Use Vieta's Theorem to solve the problems.
VladimirAG [237]

Answer:

The answer is -2, -17

Step-by-step explanation:

You write a system of equations

x_{1} +x_{2}=-19\\x_{1}-x_{2}=15

Then you solve:

-2, -17

4 0
3 years ago
Please hurry I need help
RSB [31]

Answer:

48f^2-110f+63

Step-by-step explanation:

We multiple every part of first sum with every prt of the 2nd sum:

(6f-7)(8f-9)=48f^2-54f-56f+63=

48f^2-110f+63

5 0
3 years ago
Read 2 more answers
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