A projectile is launched from ground level with an initial velocity of v0 feet per second. It's height in feet t seconds after l
aunch is given by s= -16t^2+v0t. Find the time the projectile will reach a height of 128ft when v0= 96 ft per second
1 answer:
Answer:
2345
Step-by-step explanation:
jyugtyg ytftrv g6bgy
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