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Lemur [1.5K]
2 years ago
15

When a child is born with trisomy, when did the mutation occur?

Biology
2 answers:
Lina20 [59]2 years ago
7 0

During meiosis

Apex.....

DENIUS [597]2 years ago
3 0

Answer:

during meiosis

Explanation:

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Which process will be immediately inhibited if cytochrome c is unable to interact with cytochrome c oxidase
bonufazy [111]

Answer:

Electron transfer to from cytochrome c to molecular Oxygen in the process of oxidative phosphorylation

Explanation:

Cytochrome c is a protein which is involved in the electron transport chain for the production of ATP molecules during then process of respiration. It a soluble protein found in the intermembrane space of the mitochondria. It receives electrons from ubiquinone at Complex III of the electron transport chain and transfers this electron to molecular oxygen through its interaction with complex IV or cytochrome c oxidase, reducing molecular oxygen to water.

If the interaction of cytochrome c with cytochrome c oxidase is inhibited, the process of elctron transfer to oxygen will be inhibited and, so ATP synthesis will cease.

Ultimately,  respiration will be inhibited resulting in death of the organism. For example, cyanide inhibits cytochrome c oxidase resulting in death of the organism poisoned with cyanide.

4 0
3 years ago
Describe what will occur the population if it increases in number when food is scarce?
mote1985 [20]

Answer:

more people will die

Explanation:

If you have a big population and little food mor peple will die.

4 0
3 years ago
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What is an example of prokaryotes?
oksano4ka [1.4K]

Answer: Examples of prokaryotes are bacteria and archaea.

Explanation:

3 0
2 years ago
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If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny pl
nalin [4]

Here is the complete question

The seeds in bush bean pods are each the product of an independent fertilization event. Green seed color is dominant to white seed color in bush beans.

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny plant will consist of:

A) 4 green and 2 white seeds?

B) all white seeds?

C) at least 5 white seeds?

Answer:

A) 0.3

B) 0.0002

C) 0.001

Explanation:

Let the allele for Green plant be = P

Let the allele for white plant be =  p

Let the heterozygous plant be Pp, if self fertilization occurs we have:

                   P                    p

P                 PP                 Pp                                                              

                                                           

p                 Pp                 pp                  

From the punnet square above, we have the following  cross;

PP, Pp, Pp, pp

Since P is dominant to p; we have a phenotypic ratio of 3:1 between the dominant phenotype ( PP, Pp, Pp ) and recessive phenotype ( pp )

NOW, the probability for the green plant(i.e PP or Pp) will be: Pr(G)=\frac{3}{4}

the probability for the white plant (pp) will be: Pr (W)= \frac{1}{4}

A)

what is the probability that 6 seeds in a single pod of the progeny plant will consist of 4 green and 2 white seeds?

Pr(4G2W) = (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

The probability includes the use of permutation:

Permutation(P)=\frac{6!}{(4!*2!)} * (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

= 15*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

= 0.2966

≅ 0.3

B)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of all white seeds?

Since probability for white seed = \frac{1}{4}

The probability that 6 seeds will consist of all white seeds will be = (\frac{1}{4})^6

=  2.44 × 10⁻⁴

= 0.000244

≅ 0.0002

C)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of at least 5 white seeds?

For at least 5 white seeds, the probability will consist of  5 white seeds and 6 white seeds.

For 5 white seeds; we have:

5 White  and 1 Green  Since there are 6 permutations.

The probability For 5 white seeds will therefore be :

Pr(5 seeds)=(\frac{1}{4})^5*(\frac{3}{4})^1 *6

= 7.32 × 10⁻⁴

= 0.000732

For 6 white seeds; we have:

Only one permutation for 6 whites since there will no be any presence of any green seed.

Pr(6seeds)=(\frac{1}{4})^6

= 2.44 × 10⁻⁴

= 0.000244

∴

The total probability for at least 5 white seeds =  0.000732 + 0.000244

= 9.76  × 10⁻⁴

= 0.000976

≅ 0.001

3 0
3 years ago
Which statement is correct?
tangare [24]
The first statement is absolutely correct !!

in a neutral atom, no of protons are always equal to no of electrons !!
7 0
3 years ago
Read 2 more answers
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