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Juli2301 [7.4K]
3 years ago
9

Are the triangles similar? If so, write the similarity statement and state which theorem or postulate is used to prove the two t

riangles similar.
A.
Yes, ΔABC ~ ΔEDC by the SAS similarity theorem.
B.
Yes, ΔABC ~ ΔDCE by the SSS similarity theorem.
C.
Yes, ΔABC ~ ΔDEC by the AA similarity postulate.
D.
No, these triangles are not similar.

Mathematics
2 answers:
Zigmanuir [339]3 years ago
3 0
The answer would be D) no, these triangles are not similar. I'm pretty sure they would be similar if one of the answer choices said ΔABC ~ ΔCED
Vikki [24]3 years ago
3 0

<u>Answer: </u>D.  No, these triangles are not similar.

<u>Step-by-step explanation:</u>

From the given picture, it can be seen that in Δ ABC, AB=BC=9 units

Therefore, ∠ABC=∠ACB=65°  [Angles opposite to equal sides of a triangle are equal]

Then ∠BAC=180°-∠ABC-∠ACB    [by angle sum property of triangle]

⇒ ∠BAC=180°-65°-65°

⇒ ∠BAC=50°

Similarly in ΔDEC, DA=DC=6 units, then ∠DEC=∠DCE  [Angles opposite to equal sides of a triangle are equal]

Let  ∠DEC=∠DCE=x

Then by angle sum property, in ΔDEC

∠DEC+∠DCE=180°-∠EDC

⇒ x+x=180°-46°

⇒ 2x=134°

⇒x=67°

∴∠DEC=∠DCE=67°

We can see that no two angles of both the triangles are equal.

Therefore, hese triangles are not similar.

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9 < x < 10 --- interval

Required

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Solve

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So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

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