<u>Answer: </u>D. No, these triangles are not similar.
<u>Step-by-step explanation:</u>
From the given picture, it can be seen that in Δ ABC, AB=BC=9 units
Therefore, ∠ABC=∠ACB=65° [Angles opposite to equal sides of a triangle are equal]
Then ∠BAC=180°-∠ABC-∠ACB [by angle sum property of triangle]
⇒ ∠BAC=180°-65°-65°
⇒ ∠BAC=50°
Similarly in ΔDEC, DA=DC=6 units, then ∠DEC=∠DCE [Angles opposite to equal sides of a triangle are equal]
Let ∠DEC=∠DCE=x
Then by angle sum property, in ΔDEC
∠DEC+∠DCE=180°-∠EDC
⇒ x+x=180°-46°
⇒ 2x=134°
⇒x=67°
∴∠DEC=∠DCE=67°
We can see that no two angles of both the triangles are equal.
Therefore, hese triangles are not similar.