Answer this question in the photo 18 PTS

Mathematics

1 answer:

LiRa [457]3 years ago

4 0

Question - Answer
a) 1/2 L = 4
b) 1/2 L x 4 = 2
c) 5/6 x 2 = 1 4/6 L OR 1.67 L
d) 2/3 L = 3 beakers with 2/3 OR 5 beakers with 2/3 and 5/6
e) <1/3 L = 3 beakers

I believe that is the answer.

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Trimming a garage door a carpenter used 30 ft of molding in three pieces to trim a garage door. if the long piece was 2 ft longe

Ksju [112]

Answer:

Step-by-step explanation:

3tryt

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3 years ago

Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa

Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

Let p = proportion of the students who are in favor of Mike.

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, $H_A$ : p > 50% {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students body in favor of Mike = $\frac{55}{100}$ = 0.55

n = sample of students taken = 100

So, test statistics = $\frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }$

= 1.01

The value of z test statistics is 1.01.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

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3 years ago

Click the picture that I sent you

Digiron [165]

Answer: 1211.6585 years

Step-by-step explanation:

The equation for exponential growth is: $P=P_oe^{kt}$

P: final population
P₀: initial population
k: rate of decay (or growth)
t: time

Use the half life information to find k:

$\dfrac{1}{2}P_o=P_oe^{k(800)}\\\\\\\dfrac{1}{2}=e^{800k}\qquad \rightarrow \qquad \text{divided both sides by}\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=800k\qquad \rightarrow \qquad \text{applied ln to both sides}\\\\\\\dfrac{ln(\frac{1}{2})}{800}=k\qquad \rightarrow \qquad \text{divided both sides by 800}\\\\\\\large\boxed{-0.000867=k}$