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3 years ago

‼️EXPLAIN PLS ILL MARK YOU BRAINLEST ‼️

Mathematics

1 answer:

MakcuM [25]3 years ago

4 0

Angle 3: 24 degrees- the angle across from it is 24 which makes this one 24 so it’s congruent.
Angle 1 and 4: 78 degrees- on one side of these angles (the line the seperates it running parallel) the angles total to 180 degrees, we take angle 3 which was 24 and subtract that from 180. That equals 156 which we then divide into two because we have two angles left to solve for which makes 78 each.
Angle 2: 71 degrees- We know angle 3 is 24 and we have a written angle as 85. Knowing each side of these angles equals 180 degrees, we add 85 and 24 to get 109. We then will subtract 180 from 109 to get our missing angle which is 71 degrees.

I hope I could help :)

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Please help i am very confused

Step2247 [10]

Answer:

$\sqrt{80}$

80 is the number in the square root

Step-by-step explanation:

$d = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} } \\d = \sqrt{(4-(-4) )^{2} +(5- 1 )^{2} }\\d = \sqrt{(4+4 )^{2} +4^{2}\\d = \sqrt{8^{2} +4^{2} }\\d=\sqrt{64 +16}\\d=\sqrt{80}$

4 0

3 years ago

Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).

I am Lyosha [343]

Take the homogeneous part and find the roots to the characteristic equation:

$y''+4y=0\implies r^2+4=0\implies r=\pm2i$

This means the characteristic solution is $y_c=C_1\cos2x+C_2\sin2x$ .

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form $y_p=ax\cos2x+bx\sin2x$ . Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With $y_1=\cos2x$ and $y_2=\sin2x$ , you're looking for a particular solution of the form $y_p=u_1y_1+u_2y_2$ . The functions $u_i$ satisfy

$u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx$

where $W(y_1,y_2)$ is the Wronskian determinant of the two characteristic solutions.

$W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2$

So you have

$u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx$
$u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x$

$u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx$
$u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x$

So you end up with a solution

$u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x$

but since $\cos2x$ is already accounted for in the characteristic solution, the particular solution is then

$y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x$

so that the general solution is

$y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x$

7 0

3 years ago

owen has 5/6 of a yard of sailcloth. he uses 2/3 of the cloth to recover a seat cushion. How much cloth does he use?

adelina 88 [10]

He uses 2 feet of the yard or... 4/6 hope this helped :3

3 0

3 years ago

Read 2 more answers

Hello, can you please review attached and help me with the answer ?

Elis [28]

Answer:

(a). P(x) = 8x - 112,000

(b). $80,000

Step-by-step explanation:

(a). P(x) = R(x) - C(x)

P(x) = 50x - 112,000 - 42x

P(x) = 8x - 112,000

(b). P(24,000) = 8(24,000) - 112,000 = 80,000

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(a). P(x) = 8x - 112,000

7 0

2 years ago

Cuanto costara una sala que se anuncia en $7500, con el 30% de descuento mas 16% de IVA

alexgriva [62]

Answer:

30 por ciento:2250

16 por ciento:1200

Step-by-step explanation:

4 0

3 years ago

‼️EXPLAIN PLS ILL MARK YOU BRAINLEST ‼️​

‼️EXPLAIN PLS ILL MARK YOU BRAINLEST ‼️