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Solnce55 [7]
3 years ago
8

cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph. How long will

Gabriel travel before catching up with Cesar?
Mathematics
1 answer:
Sloan [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph.

Before Gabriel started Cesar would have travelled for 4 hours

So distance travelled by Cesar in 4 hours =4(12) =48 miles

Thus Cesar is ahead of Gabriel by 48 miles

Difference of speed =(24-12) =12 mph

So to catch Cesar time required = 48/difference in speed

= 4 hours

It will take 4 hours.

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