Question

cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph. How long will Gabriel travel before catching up with Cesar?

Answer 1

Answer:

Step-by-step explanation:

Given that cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph.

Before Gabriel started Cesar would have travelled for 4 hours

So distance travelled by Cesar in 4 hours $=4(12) =48 miles$

Thus Cesar is ahead of Gabriel by 48 miles

Difference of speed $=(24-12) =12 mph$

So to catch Cesar time required = 48/difference in speed

= 4 hours

It will take 4 hours.