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miss Akunina [59]
3 years ago
13

Solve each proportion 1.5/6=10/p p=?

Mathematics
1 answer:
notsponge [240]3 years ago
4 0
6/1.5=10/p p=?
6/1.5=.25
10/2.5=.25
p=.25
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Which data set contains an outlier?
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If the fdic has an insurance fund of 67.8 billion and must use 7.6% of it to cover several failed banks, approximately how much
erastovalidia [21]
If you're using 7.6 percent, then you're not using 92.4 percent (100-7.6)

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Domain and range of the function f(x)= 7x^5<br> PLEASE HELP I LITERALLY CANT DO IT
sineoko [7]

Answer:

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

The domain is all x values, and the range is all y values.

<u><em>Domain:</em></u>

The domain is all real numbers except where the slope is undefined (a vertical line). In this case, no number makes the expression undefined, so the domain is:

all real numbers

<u><em>Interval notation:</em></u><em>  </em>(-∞,∞)

all negative numbers and positive numbers (all real numbers)

<em><u>Set-Builder Notation:</u></em> {x | x ∈ R }

<em><u>Range:</u></em>

The range is the set of all valid values. Graph the line and check. Since all values of y are valid, the range is:

all real numbers

<u><em>Interval notation:</em></u><em>  </em>(-∞,∞)

all negative numbers and positive numbers (all real numbers)

<em><u>Set-Builder Notation:</u></em> {x | x ∈ R }

:Done

3 0
2 years ago
1) What are the solutions of (x/3) &gt; -1? <br><br>is this asking if I need multiple solutions?​
BartSMP [9]

Yes...

x/3 > -1

what values of x make x/3 > -1

hint... your answer will look like like x > (number)

7 0
2 years ago
PLS HELP ME!!! which matrix represents the system of equations below {8x-9y+13z=11
Finger [1]

Answer:

The answer is below

Step-by-step explanation:

The system of equations:

8x-9y+13z=11

-8x-5y+5z=15

3x+4y-8z=-10

The equations can be represented in matrix form as:

AX = B

X = A⁻¹B

Therefore:

\left[\begin{array}{ccc}8&-9&13\\-8&-5&5\\3&4&-8\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}11\\15\\-10\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}8&-9&13\\-8&-5&5\\3&4&-8\end{array}\right] ^{-1}\left[\begin{array}{c}11\\15\\-10\end{array}\right]\\

\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}\frac{1}{19} &-\frac{1}{19}&\frac{1}{19}\\-\frac{49}{380}&-\frac{103}{380}&-\frac{36}{95} \\-\frac{17}{380}&-\frac{69}{380}&-\frac{28}{95} \end{array}\right] \left[\begin{array}{c}11\\15\\-10\end{array}\right]\\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}-0.74\\-1.69\\0.13\end{array}\right] \\

4 0
2 years ago
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