Consider a six-sided die that is loaded so that numbers 2, 3, 4, 5 and 6 are all equally likely to appear, and 1 is three times
1 answer:
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Answer:
Step-by-step explanation:
The equation for that is
If we subtract over the 70, we have a quadratic that we can factor to solve for the values of x that will make that equation true.
Now we need the factors of 70 that will either add or subtract to give us the linear term of 3. The factors of 70 that will work are 10 and 7. 10 times 7 is 70, and 10 - 7 = 3:
and now we will factor by grouping:
and factor out what's common:
The factor (x + 10) is common, so we will now factor that out:
By the Zero Product Property, either x + 10 = 0 or x - 7 = 0, so x = -10 or 7
Those are the 2 numbers that will work.
simplifies to
100 - 30 which does in fact equal 70. OR
which simplifies to
49 + 21 which also equals 70.
So you're done!