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Nadusha1986 [10]
3 years ago
5

ABC or D I need help I’ll give brainly

Mathematics
1 answer:
zimovet [89]3 years ago
8 0

Answer: B. -3

I hope this helps you.

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Find the radius of a sphere with a volume of 972π cubic millimeters.
sesenic [268]

Answer:

The radius is 9 mm

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3  where r is the radius

972 pi  = 4/3 pi r^3

Divide each side by pi

972 = 4/3 r^3

Multiply each side by 3/4 to isolate r^3

3/4 * 972 = 4/3 * 3/4 r^3

729 = r^3

Take the cube root of each side

(729) ^ (1/3) = (r^3) ^ (1/3)

9 = r

The radius is 9 mm

8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIST
madam [21]

Answer:

Ted

Step-by-step explanation:

4 0
3 years ago
Find the solution by graphing the equations pls help
lilavasa [31]

Answer:

graph these
y = 2x + 2
y = 2x - 3

Step-by-step explanation:

2x - y = -2
2x - y = 3

convert to y intercept form
first
2x - y = -2
-y = -2x - 2
y = 2x + 2
second
2x - y = 3
-y = -2x + 3
y = 2x - 3

you are left with
y = 2x + 2
y = 2x - 3
i cannot graph these for you, but i assume you know how, there is no solution because the lines are parallel

4 0
3 years ago
How do you to tell the difference between an ellipse, hyperbola, parabola, or circle if all are in standard form?
NeX [460]

Step-by-step explanation:

General form of a conic section is:

Ax² + Bxy + Cy² + Dx + Ey + F = 0

If B = 0:

Parabola: Either x² or y² term, but not both

Circle: x² and y² have the same coefficient

Ellipse: x² and y² have different positive coefficients

Hyperbola: x² and y² have different signs

Otherwise, look at the discriminant.

If B² − 4AC < 0, then the conic is an ellipse.

If B² − 4AC = 0, then the conic is a parabola.

If B² − 4AC > 0, then the conic is a hyperbola.

6 0
3 years ago
What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)
xxMikexx [17]
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)

we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment  is 3√2

see the attached figure

3 0
3 years ago
Read 2 more answers
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