My sister used 2 1/2 yards of my frabic for a project. This was 2/3 of my frabic. How much frabic did i have at the start?
1 answer:
You might be interested in
By substitution,
and so on, so that
[tex]g(n)=6.1^{n-1}g(1)=2.7\cdot6.1^{n-1}
By substitution,
and so on, so that
[tex]g(n)=6.1^{n-1}g(1)=2.7\cdot6.1^{n-1}