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Finger [1]
3 years ago
7

Homes in your neighborhood appreciates at a rare Of 3.5% annually. The family purchase a home in your neighborhood with a value

of 160,000 at this rate how many years will it take for the home to be valued at 250,000
Mathematics
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer: it will take 13 years for the home to be valued at 250,000

Step-by-step explanation:

The growth rate is exponential. We would apply the formula for exponential growth which is expressed as

y = b(1 + r)^ t

Where

y represents the value of the house after t years.

t represents the number of years.

b represents the initial value of the house.

r represents rate of growth.

From the information given,

b = 160000

y = 250000

r = 3.5% = 3.5/100 = 0.035

Therefore

250000 = 160000(1 + 0.035)^t

250000/160000 = (1.035)^t

1.5625 = (1.035)^t

Taking log of both sides to base 10

Log 1.5625 = log1.035^t = tlog1.035

0.1938 = t × 0.0149

t = 0.1938/0.0149

t = 13 years

almond37 [142]3 years ago
6 0

Answer:

In 13 years the home to be valued at 250,000.

Step-by-step explanation:

Present value of home = 160000

Annual increasing rate of the home = 3.5 %

Final value of home is = 250000

Let this value of  home becomes after t years.

⇒ 250000 = 160000 (\frac{103.5}{100})^{T}

⇒ 1.5625 = 1.035^{T}

⇒ ㏑ 1.5625 = T ㏑ 1.035

⇒ T = 13 years

Therefore in 13 years the home to be valued at 250,000.

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Solve for xxx. Write the smaller solution first, and the larger solution second.
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Answer:

x=-5\text{ or }x=2

Step-by-step explanation:

We have been given an equation x^2+3x-10=0. We are asked to find the solutions of our given equation.

We will use splitting the middle term method to solve quadratic equation.

We will split middle term of our given equation into parts such that whose product is -10 and whose sum is 3.

We know that such two numbers are 5\text{ and }-2.

x^2+5x-2x-10=0

(x^2+5x)+(-2x-10)=0

x(x+5)-2(x+5)=0

(x+5)(x-2)=0

Using zero product property, we will get:

(x+5)=0\text{ or }(x-2)=0

x+5=0\text{ or }x-2=0

x=-5\text{ or }x=2

Therefore, the solutions for our given equation are x=-5\text{ or }x=2.

4 0
2 years ago
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lianna [129]

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3 years ago
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Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.<b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

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Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
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