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3 years ago

Hi, please help mec - 4d =C= 10D=2It's algebra

Mathematics

1 answer:

Inessa [10]3 years ago

7 0

Answer:

All you do is replace the variable with the numbers given to replace them.

So your new equation is 10-4(2) this was given to you C=10 , D=2

Okay, let's solve it 10-4(2)

4*2 equals 8 so now it's 10-8

10-8

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In the figure, angle D measures 45° and angle E measures 87°. What is the measurement of angle H? 42°

Vinvika [58]

The complete question is shown in the attached image

Answer:
measure angle H = 42°

Explanation:
There is a theorem that states that:
"In a triangle, the measure of the exterior angle is equal to the sum of the measures of the two non-adjacent angles to the exterior angle"

In the given, we have:
angle E is an exterior angle to triangle DFH
The two non-adjacent angles to angle E are angles D and H

Based on the above rule:
measure angle E = measure angle D + measure angle H

We are given that:
angle E = 87°
angle D = 45°

Substitute with the givens in the above rule and solve for the measure of angle H as follows:
angle E = angle D + angle H
87° = 45° + measure angle H
measure angle H = 87° - 45°
measure angle H = 42°

Hope this helps :)

3 0

3 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago

I need help I don't understand it at all

DedPeter [7]

Answer:

x = 9

Step-by-step explanation:

Given

5x - 31 = 23 - x ( add x to both sides )

6x - 31 = 23 ( add 31 to both sides )

6x = 54 ( divide both sides by 6 )

x = 9

8 0

3 years ago

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A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.1 ft/s,

pishuonlain [190]

let:
X = the distance of the bottom of the ladder from the wall at any time
dX/dt = rate of travel of the bottom of the ladder = 1.1 ft/sec
A = the angle of the ladder with the ground at anytime
dA/dt = rate of change of the angle in radians per second

X = 10 cos A

dX/dt= -10 sin A dA/dt = 1.1

dA/dt = -1.1/(10 sinA)

When X = 6; cosA = 6/10; sinA = 8/10

Therefore:

dA/dt = -1.1/(10 x 0.8) = -0.1375 radiant per second.

4 0

3 years ago

A box of 12 Popsicles costs $4.44 what is the Popsicles unit rate

OLEGan [10]

The unit rate would be $0.37

4 0

3 years ago

Read 2 more answers

Hi, please help mec - 4d =C= 10D=2It's algebra​

Hi, please help mec - 4d =C= 10D=2It's algebra