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Dvinal [7]
3 years ago
7

How to do the problem

Mathematics
1 answer:
Veronika [31]3 years ago
8 0
Ill work it out w/ the steps so you can do it later on. STEP 1) multiply 95 by .10 to get 9.5 STEP 2) subtract 9.5 from 95 to get 85.5, your new price STEP 3) multiply 85.5 by 1.045 *mini step to get 1.045: add 4.5 to 100, get 104.5, divide by 100, get 1.045* then you get $89.35  
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Josiah, Nathaniel and Walden work 7,5, and 3 days respectively on a particular job. If the payment for the job is $216.00, how m
stira [4]
100.80 that’s how much he received
7 0
2 years ago
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Gnom [1K]

Answer:

ask to your teachers and you will be finish the work

3 0
2 years ago
Identify the parent function. 5 --5<br>a absolute <br>b reciprocal<br>c cube root<br>d square root​
velikii [3]

Step-by-step explanation:

For an absolute value function, the graph will look like an arrow with a sharp inflection point.

Reciprocal function will tend towards a limit when stretched to infinity.

Cube root and square root functions do not tend towards infinity at x = 0, because it is either 0 or the constant value.

The best answer here is Reciprocal. (B)

5 0
3 years ago
Read 2 more answers
Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
Alona [7]

Answer:

We have the equation

c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

4 0
3 years ago
Aubrey claims that if the dimensions of the parallelogram shown are doubled, then the area of the larger parallelogram will be 4
Ostrovityanka [42]

Answer:

Aubrey is correct because the area of the new parallelogram is 12 (6) = 72 square inches. The original area is 18 square inches. Since 4 (18) = 72, the new parallelogram has 4 times the area of the original.

Step-by-step explanation:

A parallelogram with a base of 6 inches and height of 3 inches. A side has a length of 5 inches.

Aubrey is correct because the area of the new parallelogram is 12 (6) = 72 square inches. The original area is 18 square inches. Since 4 (18) = 72, the new parallelogram has 4 times the area of the original.

Aubrey is correct because the area of the new parallelogram is 10 (7) = 70 square inches. The original area is 18 square inches. Since 4 (18) = 72, it is about 4 times larger than the original.

Aubrey is incorrect because if one doubles each dimension, then the area will automatically be doubled as well. The original area is 18 square inches so the new parallelogram will have an area of 2 (18) = 36, or two times more than the original.

Aubrey is incorrect because if one doubles each dimension, then the area will automatically be doubled as well. The original area is 30 square inches so the new parallelogram will have an area of 2 (30) = 60, or 2 times more than the original.

Workings

Area of a parallelogram=base×height

Original parallelogram

Base=6 inches

Height=3 inches

Area=base×height

=6×3

=18 square inches

New parallelogram with doubled dimensions

Base=6 inches doubled=12 inches

Height=3 inches doubled=6 inches

Area=base×height

=12×6

=72 square inches

New area=4 times original area

New area=4×18

New area=72 square inches

5 0
2 years ago
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