Answer:
1st answer is d, 2nd answer is d ,3rd answer is d, 4th answer is c,5th answer is c and 6th answer is c
Step-by-step explanation:
- By using first difference GP on the series 5,7,11,19,35.........
we get the series 2,4,8,16.................
The general term for first difference GP we have an=c×2∧n+d
by putting n=1 we get 5=2c+d and by n=2 we get 7=4c+d
By solving the two equations we get c=1 and d=3
an=2∧n+3
2. tn+1= -1×tn+3
By analysis the option we get tn=4 then we tn+1=-1 so only d option
satisfy the condition rest options don't satisfy so answer is option d
3. Given t1=5 and the condition is given that tn+1=3×tn
putting n=1 we get t2=3×t1
∵By substituting we get t2=3×5=15
4. The sequence is given as 8,11,14,17,20,23,26
This is an A.P. so the general term of A.P. is given as tn=t(n-1)+d
where t(n-1)is the previous term and d is the common difference which
is equal to 3 in this case
∵The answer is tn=t(n-1)+3
5.The sequence is given as 5,8,11,14,17................................. we have to find
the 43rd term of the sequence
The given sequence is an A.P.
∵The general term is an=a+(n-1)d where a is the first term and d be
the common difference which is equal to 3 in this case
We have to find the 43rd term so n=43
By substituting in the given equation we get a43=5+(43-1)×3=129
∴The 43rd term of the given sequence is equal to 129
6. When we count the boxes we get that they follow a pattern given as
1,5,9,13................ This follow an series of A.P.
∵ The general term is an=a+(n-1)d where a is the first term and d be the
common difference which is equal to 4 in this case
we have to find the number of boxes in 10th step of pattern so n=10 for
case a10=1+(10-1)×4=37
∴The number of boxes in the 10th step is 37
