Answer:
Step-by-step explanation:
a) True. Let I integer = 2m+1 and second integer 2n+1
Difference = 2(m-n) hence even
b)False. If m and n are integers and m+n is odd then either both even or both odd
Eg: 3 and 5. 3+5 =8 is even but both are even
c) True
m is odd then m= 2n+1
l is even so l = 2p
Sum = 2(n+p)+1 hence odd
Answer:
C D H
Step-by-step explanation:
The best way to tackle this problem is to put each answer into the equation and evaluate the equation.
for example
-(-3.9) + 6 >= 10
3.9 + 6 >= 10
9.9 >= 10 .this is not true!
be very careful with the signs and evaluate each answer.
Hello!
To amount to 1.50, she needs to add .45.
Answer:
Step-by-step explanation:
See attachment 1. This is the formula to use.
There are two numbers, so n=2. Plugging them into the formula, you get
![\sqrt[2]{6*\frac{1}{2}} \\](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B6%2A%5Cfrac%7B1%7D%7B2%7D%7D%20%5C%5C)
Now, putting a 2 in front just means we're finding the square root, so I'll get rid of it. Then, just do the calculation.
F(x) is another way to say “y” so you could also write, y=2(x+6)-4, and it’s asking what does x equal if y is 6, so you substitute 6 for y.
6=2(x+6)-4
6=2x+12-4
6=2x+8
-2=2x
-1=x
