Answer: (B)
Explanation: If you are unsure about where to start, you could always plot some numbers down until you see a general pattern.
But a more intuitive way is to determine what happens during each transformation.
A regular y = |x| will have its vertex at the origin, because nothing is changed for a y = |x| graph. We have a ray that is reflected at the origin about the y-axis.
Now, let's explore the different transformations for an absolute value graph by taking a y = |x + h| graph.
What happens to the graph?
Well, we have shifted the graph -h units, just like a normal trigonometric, linear, or even parabolic graph. That is, we have shifted the graph h units to its negative side (to the left).
What about the y = |x| + h graph?
Well, like a parabola, we shift it h units upwards, and if h is negative, we shift it h units downwards.
So, if you understand what each transformation does, then you would be able to identify the changes in the shape's location.
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Answer:
Option (A)
Step-by-step explanation:
Te given equation is,
-qx + p = r
Toe find the value of x,
By subtracting p from both the sides of the equation.
-qx + p - q = r - q
-qx = r - q
By dividing the whole equation by (-q),

x = 
x = 
Therefore, Option (A) will be the answer.
Answer:How many miles can a car be driven in 3 hours at 50 miles per hour? Under normal circumstances and the generally assumed conditions, the answer is of course (3 hours) * (50 miles / hour) = 150 miles.
3.5 hours
It will take you 3.5 hours to go 280 miles at 80 miles an hour.It travels at constant speed for the remaining time. Let x be the time traveled at the unknown constant speed. The total itme for the trip was 6 hours so: 6 = time traveled at 50 mph + time traveled at 60 mph + time traveled at x mph.
Step-by-step explanation:So you drive 25 miles / hour. then 25 miles/ 1 hour = 225 miles / nb of hours.2 minutes
However, traveling at 30 MPH for 1 mile (1 lap) takes 2 minutes, which means that your average will never be 60MPH.approximately 0.6818 miles per hour.
It is B because I had the question before in my school