Which is the equation of a line that passes through the points (-2,6) and (2,0)?
2 answers:
First we need to find the slope:
m = 0 - 6 / 2 + 2 = -6/4 = -3/2
So, the slope is -3/2.
Next we need to find the y-intercept:
0 = -3/2(2) + b
0 = -3 + b Multiply.
3 = b Add 3 to each side.
b = 3 Switch the equation around.
Now we can write the equation:
y = -3/2x + 3
Answer: y = -3/2x + 3
That is slope - intercept form.
There are two other ways you can write equations for lines.
There is also point slope form.
y - y1 = m(x - x1)
y - 6 = -3/2 (x + 2)
Answer: y - 6 = -3/2 (x + 2)
There is one more way we can write an equation for a line.
It is called standard form.
Ax + By = C
In standard form:
A, B, and C have to be integers. But, A has to be a positive integer.
y = -3/2x + 3
3/2x + y = 3
3x + 2y = 6
Answer: 3x + 2y = 6
Now you only asked for one equation, but I gave you all 3.
So here they are again:
Final Answer:
Slope - Intercept Form: y = -3/2x + 3
Point Slope Form: y - 6 = -3/2 (x +2)
Standard Form: 3x + 2y = 6
Your answer is y = -3/2x + 3
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Step-by-step explanation:
Solve for x:
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