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aleksandrvk [35]
3 years ago
8

Which ordered pair can be plotted together with these four points, so that the resulting graph still represents a function?

Mathematics
2 answers:
MrRissso [65]3 years ago
7 0

Answer:

The Answer is B - (-1,2)

Step-by-step explanation:

A function must pass the vertical line test and if you were to plot any of those points on the graph they can't be on the same vertical line as any of the other points. (-1 , 2) is the only point that would allow the graph to pass the VLT

FinnZ [79.3K]3 years ago
7 0

Answer:

The answer is b hope this is straitfoward and helps

:)

Step-by-step explanation:

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Answer:

y=x+20

Step-by-step explanation:

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Step-by-step explanation:

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4 years ago
Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

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\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

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3 years ago
Need help ASAP PLEASE DUE SOON!!!
beks73 [17]

Answer:

11

Step-by-step explanation:

all u need to do is to cube root 1331, because it is a cube. hope i helped.

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