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Ostrovityanka [42]
3 years ago
8

A cheetah can go from a state of resting to running at 20 m/s in just two seconds. What is the cheetah's average acceleration?

Mathematics
2 answers:
luda_lava [24]3 years ago
5 0

A cheetah can go from rest to running at 20m/s in 2 seconds. Plug in 2 for s

20/2

Simplify. Divide.

20/2 = 10

10 meters per second² is your average acceleration

vivado [14]3 years ago
3 0
<h2>Answer</h2>

10 m/s^2

<h2>Explanation </h2>

To solve this, we are using the average acceleration formula:

a=\frac{v_{f}-v_{i}}{t_{f}-t_{i}}

where

a is the average acceleration

v_{i} is the initial velocity

v_{f} is the final velocity

t_{i} is the initial time

t_{f} is the final time

Since the cheetah go from state of resting, the initial velocity and time are both zero, so v_{i}=0 and t_{i}=0. Now, the cheetah go from resting to 20 m/s in two seconds, so v_{f}=\frac{20m}{s} and t_{f}=2s.

Now that we have our values, let's replace them in our formula to find a:

a=\frac{\frac{20m}{s}-0}{2s-0}

a=\frac{\frac{20m}{s}}{2s}

a=\frac{\frac{20m}{s}}{2s}

a=\frac{20m}{2s^2}

a=\frac{10m}{s^2}

The average acceleration of the cheetah is 10 m/s^2

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Mariulka [41]

Answer:

Probability that detector B goes off is '0.615'

Step-by-step explanation:

Given that:

1) Probability that detector A goes off and detector B does not go off is 0.25.

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3)Probability that detector A  goes off is (1-0.35)=0.65

Assuming that

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Thus the probability that detector A goes off and detector B does not go off is  product of the individual probabilities

P(E)=0.65\times (1-p)\\\\0.65\times (1-p)=0.25\\\\0.65-0.65p=0.25\\\\0.65-0.25=0.65p\\\\\therefore p=\frac{0.40}{0.65}=0.615

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3 years ago
Find the solutions to x² = 12.
Novosadov [1.4K]

Answer:

x = \pm 2\sqrt3

Step-by-step explanation:

Hello!

Let's use the square root property to solve this question

Solve:

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The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.

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The final area that we have to determine are the side triangles.  After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles.  We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.

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~Aamira~

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