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34kurt
3 years ago
5

Seven apple women possessed respectively 20,40,60,80,100,120,and 140 apples, went to market and sold all their apples at the sam

e price,and each received the same sum of monkey.What was the price?
Mathematics
1 answer:
ra1l [238]3 years ago
3 0

Answer: Each woman sold her apples at the rate of seven apples for I¢, and 3¢ each for the odd ones which were left over. this made it possible for each to receive the same amount, which is 20¢.

Step-by-step explanation:

given data:

20,

40,

60,

80,

100,

120,

140.

solution.

first woman 20 apples

= 2 + 3 * 6¢.

= 20¢.

second woman 40 apples

= 5 + 5 * 3¢.

= 20¢.

third woman 60 apples

= 8 + 4 * 3¢.

= 20¢.

fourth woman 80 apples

= 11 + 3 * 3¢.

= 20¢.

fifth woman 100 apples

= 14 + 2 * 3¢.

= 20¢.

sixth woman 120 apples

= 17 + 1 * 3¢.

= 20¢.

seventh woman 140 apples

= 20 * 1¢.

= 20¢.

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Answer:

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Step-by-step explanation:

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so... 79+63 = 142

now...

142+8x+6=180(sum of angles in a triangle)

148+8x=180

8x=32

x=4

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3 years ago
A box of cereal has a volume of 144in^ 3 . The height of the cereal box is 12 inches , and the depth is 2 inches. What is the wi
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2 years ago
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A vehicle is traveling at a rate of 80 kilometers per hour. How many miles per hour is this?
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49.71 miles per hour

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Pls write the steps u did​
frez [133]

When two parallel lines are intersected by a transversal, the same-side exterior angles are supplementary. That means that their sum is 180.

Using that logic, if the two roads were parallel, then the sum of their same-side exterior angles will add up to 180. Yet their same-side exterior angles add up to 170 (130 + 40 = 170), hence they can't be parallel.

See the drawing attached below.

Using supplmenatry angles (two angles whose sum of measures add up to 180 or a straight line), we can say that:

m<DIE + m<HID = 18

40 + m<HID = 180

m<HID = 140

Similarly:

m<BHC + m<CHI = 180

130 + m<CHI = 180

m<CHI = 50

Using verticle angles therome, (when two lines intersect, the angles opposite to eachother are congruent, or have the same measure), we can say that:

m<DIE = m<GIH = 40

m<GIE = m<HID = 140

m<CHI = m<AHB = 50

m<BHC = m<AHI = 130

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2 years ago
The pound has three kinds of dogs: pit bull, chihuahuas and mutts. All but 23 of the dogs are pit bull, all but 17 are chihuahua
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Answer:

There are 68 dogs in the pound.

Step-by-step explanation:

Number of pit bull dogs in a pound = P = 23

Number of chihuahuas dogs in a pound = C = 17

Number of mutts dogs in a pound = M = 28

Total number of dogs in a pound = T

T = P+C+M=23+17+28=68

There are 68 dogs in the pound.

5 0
3 years ago
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