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Sladkaya [172]
3 years ago
11

HELP! IM STUCK!

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

(x-1)^2+(y+4)^2=9

Step-by-step explanation:

The equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (h, k) is the center and r is the radius.

The center of the circle is (1, -4).

And the radius is 3.

Substitute:

(x-(1))^2+(y-(-4))^2=(3)^2

Simplify. Thus, our equation is:

(x-1)^2+(y+4)^2=9

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Answer:

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Step-by-step explanation:


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3 years ago
A publishing company has a weekly cost equation of C=96,000+20x and a weekly revenue equation of R=26​x, where x is the number o
almond37 [142]
Sent a picture of the solution to the problem (s).

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3 years ago
Write an equation of the line parallel to y=3x+2 that passes through (-1, -2)
Mariulka [41]

Answer:

y=3x+1

Step-by-step explanation:

From the question, we are given;

  • The equation y = 3x + 2
  • A point (-1, -2)

We are required to determine the equation of a line parallel to the given line and passing through the point (-1, -2)

  • We are going to determine the gradient of the line first; when an equation is written in the form of y = mx + c, where m is the gradient.

y = 3x + 2, m₁ = 3

  • But, m₁ = m₂ for parallel lines
  • Therefore, the gradient of the line in question, m₂ is 3
  • With the gradient, m₂=3 , and a point (-1, -2) we can get its equation;

Taking another point (x, y)...

Then;

\frac{y+2}{x+1}=3

y+2=3(x+1)\\y+2=3x+3\\y=3x+1

Therefore; the equation of the line is y=3x+1

6 0
3 years ago
F(x)= x(x+3)(x+1)(x-4) has zeros at x=-3
anygoal [31]

Answer:  C) Sometimes positive; sometimes negative

============================================================

Explanation:

Pick a value between x = -1 and x = 0. Let's say we go for x = -0.5

Plug this into f(x)

f(x) = x(x+3)(x+1)(x-4)

f(-0.5) = -0.5(-0.5+3)(-0.5+1)(-0.5-4)

f(-0.5) = -0.5(2.5)(0.5)(-4.5)

f(-0.5) = 2.8125

We get a positive value.

This shows that f(x) is positive on the region of -1 < x < 0

----------------

Now pick a value between x = 0 and x = 4. I'll use x = 1

f(x) = x(x+3)(x+1)(x-4)

f(1) = 1(1+3)(1+1)(1-4)

f(1) = 1(4)(2)(-3)

f(1) = -24

Therefore, f(x) is negative on the interval 0 < x < 4

----------------

In short, f(x) is both positive and negative on the interval -1 < x < 4

It's positive when -1 < x < 0

And it's negative when 0 < x < 4

4 0
1 year ago
Dwayne had 136 songs on his phone. He deleted 56 songs. What is the
bazaltina [42]

136 - 56 = 80 songs kept

Ratio of songs kept to songs deleted is:

80:56

Simplify by dividing each number by 8:

The simplest form is: 10/7

8 0
3 years ago
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