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Katen [24]
3 years ago
8

Convert 8.132132132... to a rational expression in the form of a over b where b ≠ 0.

Mathematics
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:

\frac{2708}{333}

Step-by-step explanation:

0.132132132...=\frac{132}{999}=\frac{44}{333} \\\\8+0.132132132=8+\frac{44}{333}\\\\=\frac{8(333)}{333}+\frac{44}{333}\\\\=\frac{2664}{333}+\frac{44}{333}\\\\=\frac{2708}{333}

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2.30 per gallon yghehhf

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3 years ago
What is the minimum value of the graph of y=sin x assumes
Alex
Short answer: - 1
The first thing you should do is draw this or get a program to do it. I use desmos. It is included. The graph shows one complete cycle every 2*pi intervals (or 360 degrees.)

You will find no lower value that y = - 1 (nor any value greater than y = 1)


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3 years ago
Read 2 more answers
(PLEASE HELP) Find the values of x and y
777dan777 [17]

Answer:

x = 90, y = 43

Step-by-step explanation:

By the SAS theorem (as you can tell by the picture) angles B and C are similar, which means they are both 47 degrees.

Since the triangles are similar (SAS theorem) then angle x must be equal to 90 degrees, because they are on a straight line both angles would need to add up to 180 degrees.

Now that you have two angles out of three, you can solve for the last angle by setting up this equation:

B + D + A = 180

47 + 90 + A = 180

Add 47 and 90 together.

137 + A = 180

Subtract 137 from both sides.

A = 43

x = D and y = A, therefore x = 90 and y = 43.

3 0
3 years ago
Can someone help me here and check out the other two i have posted there both due soon and i have no clue how to do them
garik1379 [7]

Answer:

Since the question doesn't mention in what tide the answer should be, I will be giving a solution to both, the high and low tide. Hope this helps :)

Step-by-step explanation:

Using a cosine function, where time is measured in hours past high

tide:  y=4cos30x + 10

Using a cosine function, where time is measured in hours past low

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8 0
2 years ago
What is the value of 4*(-1+2-3+4-3+6-7+....+100) Show your work. [Pls help I am really drowning in work. 50 points + brainliest
KengaRu [80]

Answer:

200

Step-by-step explanation:

We have:

4(-1+2-3+4-5+6-7...+100)

We can rearrange the numbers to obtain:

4((-1-3-5-7-...-99)+(2+4+6...+100))

From the left, we can factor out a negative. So:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

In other words, we want to find the sum of all the odd numbers from 1 to 99.

And the sum of all the even numbers from 2 to 100.

Let's do each one individually:

Odd Terms:

We have:

(1+3+5+7+...+99)

We can use the arithmetic series formula, where:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the first term, and x_k is the last term.

Since it's all the odd numbers between 1 and 99, there are 50 terms.

Our first term is 1 and our last term is 99. So, the sum of all the odd terms are:

S=\frac{50}{2}(1+99})

Divide the fraction. Add within the parentheses:

S=25(100)

Multiply:

S=2500

So, the sum of all the odd terms is 2500.

Even Terms:

We have:

(2+4+6+...+100)

Again, we can use the above formula.

Our first term is 2, last term is 100. And since it's from 2-100, we have 50 even terms. So:

S=\frac{50}{2}(2+100)

Divide and add:

S=25(102)

Multiply:

S=2550

We originally had:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

Substitute them for their respective sums:

4(-(2500)+2550)

Multiply:

4(-2500+2550)

Add:

=4(50)

Multiply:

=200

So, the sum of our sequence is 200.

And we're done!

Note: I just found a <em>way</em> easier way to do this. We have:

4\cdot(-1+2-3+4-5+6-7+...+100)

Let's group every two terms together. So:

=4((-1+2)+(-3+4)+(-5+6)...+(-99+100))

We can see that they each sum to 1:

=4((1)+(1)+(1)+...+(1))

Since there are 100 terms, we will have 50 pairs, so 50 times 1. So:

=4(50)

Multiply:

=200

Pick which one you want to use! I will suggest this one though...

Edit: Typo

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3 years ago
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