Kyle determines that y ≥ − 8/3 x-4 is shown on the graph. Is Kyle correct? If not, determine the correct inequality.
1 answer:
Answer:
C) No, Kyle is incorrect. The correct inequality is
Step-by-step explanation:
This graph has a <em>dashed</em><em> </em><em>line</em>,<em> </em>so it would be either <em>less</em><em> </em><em>than</em><em> </em>or <em>greater</em><em> </em><em>than</em>.<em> </em>The only way to find out is to use the zero-interval test [test point (0, 0)] to ensure whether we share the opposite portion [the portion that does not contain the origin] or the portion that DOES contain the origin. This is where we verify the inequality as false or true:
<em>Greater</em><em> </em><em>than</em>
☑
<em>Less</em><em> </em><em>than</em>
This graph is shaded in the portion of the origin, so we choose the <em>greater</em><em> </em><em>than</em><em> </em>inequality statement.
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Answer:
d) 10
Step-by-step explanation:
x ÷ + 8 = 13
substitute 10 for x:
⇒ 10 ÷ + 8 = 13
solve:
1) divide 10 by
⇒ 10 ÷ = 5
2) add 8 to 5
⇒ 8 + 5 = 13
The missing figure is attached
(i) m∠APB = 90° ⇒ proved
(ii) AD = DP and PB = PC = BC ⇒ proved
(iii) DC = 2 AD ⇒ proved
Step-by-step explanation:
ABCD is a parallelogram in which:
- m∠A = 60°
- The bisectors of ∠A and ∠B meet DC at P
In parallelogram ABCD:
∵ m∠A = m∠C ⇒ opposite angles
∵ m∠A = 60°
∴ m∠C = 60°
∵ m∠A + m∠B = 180 ⇒ two adjacent supplementary angles
∴ 60 + m∠B = 180 ⇒ subtract 60 from both sides
∴ m∠B = 120°
∵ m∠B = m∠D ⇒ opposite angles
∴ m∠D = 120°
∵ AP is the bisector of angle A
- That means AP divide ∠A into two equal parts
∴ m∠BAP = m∠DAP = m∠A
∴ m∠BAP = m∠DAP = (60°)
∴ m∠BAP = m∠DAP = 30°
∵ BP is the bisector of angle B
- That means BP divide ∠B into two equal parts
∴ m∠ABP = m∠CBP = m∠B
∴ m∠ABP = m∠CBP = (120°)
∴ m∠ABP = m∠CBP = 60°
(i)
In ΔAPB
∵ m∠BAP = 30° ⇒ proved
∵ m∠ABP = 60° ⇒ proved
- Sum of the measures of the interior angles in a Δ is 180°
∴ m∠APB + m∠BAP + m∠ABP = 180°
∴ m∠APB + 30 + 60 = 180
- Add like terms in the left hand side
∴ m∠APB + 90 = 180
- Subtract 90 from both sides
∴ m∠APB = 90°
(ii)
In Δ ADP:
∵ m∠D = 120° ⇒ Proved
∵ m∠DAP = 30° ⇒ proved
- Sum of the measures of the interior angles in a Δ is 180°
∴ m∠APD + m∠DAP + m∠D = 180°
∴ m∠APD + 30 + 120 = 180
- Add like terms in the left hand side
∴ m∠APD + 150 = 180
- Subtract 150 from both sides
∴ m∠APD = 30°
∵ m∠DAP = m∠APD = 30°
- If two angles in a triangle are equal in measures, then the triangle
is isosceles
∴ Δ ADP is an isosceles triangle
∴ AD = DP
In Δ BPC:
∵ m∠PBC = 60° ⇒ proved
∵ m∠C = 60° ⇒ proved
- Sum of the measures of the interior angles in a Δ is 180°
∴ m∠BPC + m∠PBC + m∠C = 180°
∴ m∠BPC + 60 + 60 = 180
- Add like terms in the left hand side
∴ m∠BPC + 120 = 180
- Subtract 120 from both sides
∴ m∠BPC = 60°
∵ m∠PBC = m∠C = m∠BPC = 60°
- If the three angles of a triangle are equal in measure, then
the triangle is equilateral
∴ Δ BPC is an equilateral triangle
∴ PB = PC = BC
(iii)
∵ AD = BC ⇒ opposite sides in parallelogram
∵ AD = DP ⇒ Proved
- Equate the two right hand sides of AD
∴ BC = DP
∵ BC = PC
- Equate the right hand sides of BC
∴ DP = PC
∵ DC = DP + PC
∵ DP = AD
∴ PC = AD
- Substitute DP by AD and PC by AD in CD
∴ CD = AD + AD
∴ DC = 2 AD
Learn more:
You can learn more about parallelogram in brainly.com/question/6779145
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