Question

How many solutions doe

Answer 1

Answer:

Given equation have two solutions.

x = $-\frac{5}{2} and -\frac{8}{3}$

Right option is (D)

Step-by-step explanation:

We have given,

$6x^{2} +40=-31x$

we can rewrite this equation in the form given as:

6x² + 40 + 31x = 0

or 6x² + 31x + 40 = 0

On solving this quadratic equation, we get :

x = $-\frac{5}{2} and -\frac{8}{3}$

That means, given equation have two solutions.

Right option is (D)

Answer 2

Answer:

Option D is correct, i.e. two solutions.

Step-by-step explanation:

Given the equation is 6x² + 40 = -31x.

Rearranging the terms:- 6x² +31x +40 = 0.

Then a = 6, b = 31, c = 40.

Finding Discriminant as follows:-

D = b² -4ac

D = 31² -4*6*40

D = 961 - 960

D = 1

If we have positive value of D, then it has two real solutions.

Hence, option D is correct, i.e. two solutions.