<span>(18<span>t<span><span>^2</span><span> </span></span></span>+ 9<span>t^<span><span>2</span><span></span></span></span>) + (−7t −3t) + 20
</span><span><span>27<span>t<span><span>^2</span><span> </span></span></span>− 10t + 20</span><span>
</span></span><span>
</span>
Answer:
ASA
Step-by-step explanation:
You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.
Answer:
x = 109
Top Right Angle = 109
Bottom Right Angle = 71
Step-by-step explanation:
Notice the two right angles on the left and recognize that the figure is a a quadrilateral (4 sides). That means it adds up to a total of 360 degrees.
(x-38) + x + 90 + 90 = 360
2x + 142 = 360
2x = 218
x = 109
(x - 38) = (109 - 38)
71 degrees for bottom right angle
109 for top right angle
Answer:
The answer is w<6
Step-by-step explanation:
