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Luba_88 [7]
3 years ago
14

What is an equation of the line that is perpendicular to y=-4/5x+3 and passes through the

Mathematics
1 answer:
katrin2010 [14]3 years ago
5 0

Answer:

y= (5/4)x + 7

Step-by-step explanation:

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What is the equation of the line that passes through the point (3,4) and has an undefined slope?
rosijanka [135]

Answer:

The equation of the line that passes through the point (3,4) and has an undefined slope is x = 3

Step-by-step explanation:

  • The slope of the horizontal line is zero
  • The equation of the horizontal line passes through the point (a, b) is y = b
  • All the points on the horizontal line have the same y-coordinates

  • The slope of the vertical line is undefined
  • The equation of the vertical line passes through the point (a, b) is x = a
  • All the points on the vertical line have the same x-coordinates

Let us solve the question

∵ The line has an undefined slope

∴ The line is a vertical line

∵ The equation of the vertical line is x = a, where a is the x-coordinate

   of any point on the line

∵ The line passes through the point (3, 4)

∴ a = 3

∴ The equation of the line is x = 3

The equation of the line that passes through the point (3,4) and has an undefined slope is x = 3

5 0
3 years ago
The product of x and y increased by 2
nataly862011 [7]

Answer:

x*y+2

Step-by-step explanation:

6 0
3 years ago
The value of y is ___ the value of x.<br><br>Write the equation
Keith_Richards [23]
The value of y is 1.25 the value of x. 

e.g. 6.4 * 1.25 = 8.

Hope this helps! Have a great day :)
5 0
3 years ago
Read 2 more answers
Here is your questions
viva [34]

Answer:

Step-by-step explanation:

strategy:  find the distance of the two points,   take half of that,  b/c that will be the radius,   Then use   the area of a circle formula to find the answer

P1 = (1,-1)   in the form (x1,y1)

P2= ((3,3)  in the form (x2,y2)

dist = sqrt [ (x2-x1)^2 + (y2-y1)^2 ]

dist = sqrt [ 3 -1 )^2 + 3-(-1)^2 ]

dist = sqrt [ 2^2 + 4^2 ]

dist = sqrt [ 4 + 16 ]

dist = sqrt [20]

r = \sqrt{20} /2

area of circle = \pir^{2}

area of circle = \pi(\sqrt{20} /2)^2

area of circle = \pi(\sqrt{20} /2)(\sqrt{20} /2)

area of circle = \pi(20 / 4)

area of circle = \pi5

area of circle = 5\pi

3 0
3 years ago
There was a boy and he had three friends what is a multiplication sentence to find the total
KATRIN_1 [288]
X·3= or X3= And then find the answer


6 0
3 years ago
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