What is an algebraic expression for the following word phrase: "6 times the difference of g and 3"

What is the mad of 6,8,10

lana [24]

Answer:

6 + 8 + 10 = 24 ÷ 3 = 8

8 - 6 = 2

8 - 8 = 0

8 - 10 = 2

2 + 0 + 2 = 4 ÷ 3 = 1.3

your mad would be 1.3

4 0

3 years ago

Solve for p. i = prt p = i-rt p = (rt)/i p = i/(rt)

andrezito [222]

Answer:

$\sf p = \dfrac{i}{rt}$

Step-by-step explanation:

Solve for p:

$\longrightarrow$ i = prt

i = prt is equivalent to prt = i:

$\longrightarrow$ prt = i

Divide both sides by rt:

$\longrightarrow$ $\sf \dfrac{prt}{rt} = \dfrac{i}{rt}$

$\sf \dfrac{prt}{rt} = p:$

$\longrightarrow$ $\sf p = \dfrac{i}{rt}$

6 0

3 years ago

You tape two pieces of paper together that each measure

sertanlavr [38]

Answer:

The paper is 60.73 cm long.

Step-by-step explanation:

The two pieces of paper each measure 41.36 cm, so those together would be 82.72 cm. Subtracting the 21.99 that is cut off, you're left with 60.73 cm. Hope this helped!

8 0

3 years ago

Read 2 more answers

PLEASE I ONLY HAVE 30 MIUNUTES TO FINISH!!!!!!!!!!!!!

creativ13 [48]

Answer:

When it is small & when the sample has things that are different from the population.

Step-by-step explanation:

A small sample has less chance of accurately reflecting a population & too many variables can also negatively influence the study.

3 0

3 years ago

Read 2 more answers

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago