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3 years ago

The ages of the 11 players of a soccer team on the soccer field are shown 21,32,22,28,26,30,29,24,22,24,26

Mathematics

2 answers:

weqwewe [10]3 years ago

8 0

Answer:

B. Replace a 26 year old player with a 24 yearold player

hope it is helpful to you

bekas [8.4K]3 years ago

7 0

Answer:

B is the answer of the following question...

I hope it is correct !

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A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coin

Alenkinab [10]

Answer:

(35k + 20) cents

Step-by-step explanation:

First of all, let us have the value of each unit:

1 quarter = 25 cents

1 nickel = 5 cents

1 dime = 10 cents

Given that number of quarter = k

Quarters are 5 lesser than Nickels, so number of nickels = k+5

One more than twice as many dimes as quarters:

k = 2 $\times$ Number of Dimes + 1

So, number of dimes = $\frac{1}{2}(k-1)$

Value of quarters = $25 \times k$ cents

Value of nickels = $5 \times (k+5) = (5k+25)\ cents$

Value of dimes = $\frac{1}{2}(k-1) \times 10 = (5k-5)\ cents$

So, total value of coins =

$25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents$

5 0

3 years ago

Read 2 more answers

What is the center of the circle for this equation:<br> (x - 10)² + (y - 10)² = 25

Nastasia [14]

Answer:

Step-by-step explanation:

center: (-2,3)

Radius: 5

3 0

3 years ago

Slope = -3; y-intercept = 2

Stels [109]

Answer:

y= -3x+2

Step-by-step explanation:

6 0

2 years ago

Which of the following functions are an example of exponential growth ?

yanalaym [24]

Answer:

i don't know maybe D. 2 and 3

8 0

2 years ago