Answer:
(2n-1)(n-5)
Step-by-step explanation:
2n2-11n+5
2n2-10n-1n+5
(factorize)
2n(n-5)-1(n-5)
(2n-1)(n-5)
Answer:
about 0.177 mg/mL
Step-by-step explanation:
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0
Solving for t gives ...
t = 1/2.802
So, the maximum C(t) is ...
C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL
The maximum average BAC during the first 6 hours is about 0.177 mg/mL.
_____
The maximum occurs about 21 minutes 25 seconds after consumption.
51-38=8 and 44-38=8 are both equivalent
Do long division and you will get 1.95, hope I helped.