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Rasek [7]
3 years ago
8

the length of a triangle are 3cm and 10cm whats are the upper and lower on the 3rd side of the triangle?

Mathematics
1 answer:
Sidana [21]3 years ago
7 0

3^2+10^2=109

Te square root of 109= 10.44

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Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42-m-42-m squar
oee [108]

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

Total area = 1764 + 2769.48

= 4533.48 square meters

The area enclosed by the figure is 4533.48 square meters.

7 0
3 years ago
What is the volume of a shipping cube with dimensions of 2 and 1/2 feet
Fantom [35]

For this case we have that by definition, the volume of a cube is given by:

V = l ^ 3

Where:

l: It's the side of the cube

According to the statement data:

l = 2 \frac {1} {2} = \frac {2 * 2 + 1} {2} = \frac {5} {2}

Substituting in the formula we have:

V = (\frac {5} {2}) ^ 3\\V = \frac {5 ^ 3} {2 ^ 3}\\V = \frac {125} {8}\\V = 15.625

Thus, the shipping cube volume is15.625 \ ft ^ 3

Answer:

15.625 \ ft ^ 3

6 0
3 years ago
Pluto is looking into joining a gym. He has a budget of $68 per month. The gym he wants to join has fees based on the number of
Artist 52 [7]
7(10 visits) ≤ 68
70 ≤ 68
Not Viable


7(9 visits) ≤ 68
63 ≤ 68
Viable


The first solution is not viable because 10 visits will give a total cost of $70 per month, which is $2 over his monthly budget of $68.

The second solution is viable. He could visit the gym a maximum of 9 times per month for a total of $63 a month and that will be under his $68 monthly budget.

Hope this helps! :)
6 0
3 years ago
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