Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
<span>D. 11.77 grams, because (7.05 ⋅ 1.67) ⋅ (1023 ⋅ 10-24 ) = 11.7735 Question 16
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The answer would be A because you would just plug in 2 everywhere where you see x
Answer:
volume = wide x length x deep
= 3{1/3} ft x 2{1/2} ft x 3{3/4}ft
= 10/3ft x 5/2ft x 15/4ft
= (10 x 5 x 15)/(3 x 2 x 4) ft^3
= 125/4 ft^3
= 31{1/4} ft^3
Step-by-step explanation: