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Rasek [7]
3 years ago
8

the length of a triangle are 3cm and 10cm whats are the upper and lower on the 3rd side of the triangle?

Mathematics
1 answer:
Sidana [21]3 years ago
7 0

3^2+10^2=109

Te square root of 109= 10.44

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1-tan^2(x)/sec^2 = cos(2x)
LekaFEV [45]

By applying the formula of trigonometric function the right hand side will

be equal to right hand side which is 1-tan^{2} x/sec^{2}x=cos2x.

Given: 1-tan^{2} x/sec^{2}x=cos2x.

Taking right hand side first which is cos2x.

We know that cos2x=1-tan^{2}x/1+tan^{2}x

Now we will solve the left hand side of the equation give which is

1-tan^{2} x/sec^{2}x

=1-tan^{2}x/1+tan^{2}x

[secant square x minus tangent square x is equal to 1]

By putting both values left hand side and right hand side we will find our solution which is :

1-tan^{2}x/1+tan^{2}x=1-tan^{2}x/1+tan^{2}x.

Hence proved

Learn more about trigonometric functions at brainly.com/question/24349828

#SPJ10

3 0
2 years ago
A pharmacist weighed eight different capsules of the same compound and recorded these measurements: 2312 mg, 2313 mg, 2315 mg, 2
Orlov [11]

median = 2317

mean = 2,316.875

8 0
3 years ago
Draw a line representing “rise” and line representing the “run of the line state the slope of the line .state the slope of the l
Scorpion4ik [409]

Answer:

  slope 4/5

Step-by-step explanation:

The attachment shows the rise in green (4 grid squares), and the run in red (5 grid squares). The slope is the ratio rise/run.

__

The slope is rise/run = 4/5.

5 0
2 years ago
Andrew can jog 144 miles in 11 hours. Enter the number of miles he can jog in 1 hour.​
katrin2010 [14]
144/11= 13.09

Andrew can jog 13.09 miles in one hour.
8 0
3 years ago
A rectangular pyramid has a volume of 160 cubic feet. Find two possible sets of measurements for the base area and height of the
muminat

\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ \cline{1-1} V=160 \end{cases}\implies 160=\cfrac{Bh}{3}\implies 480=Bh \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} 480=&2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 5\\ &8\cdot 60\\ &32\cdot 15 \end{cases}~\hspace{5em}\stackrel{B}{8}\times\stackrel{h}{60}\qquad \qquad \stackrel{B}{32}\times\stackrel{h}{15}

4 0
3 years ago
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