What is the value of tan D?
1 answer:
Hey there!
As according to the mathematical acronym SOH CAH TOA (Sin Opposite Hypotenuse, Cos Adjacent Hypotenuse, Tan Opposite Adjacent), the correct answer would be the first choice,
.
The reason behind this is because the tangent value of an angle is always the length value opposite of given angle over the value adjacent (or right next to) the given angle.
In this case, the question is asking for Tan D. The side value opposite of angle D would be 12, and the length value that is adjacent to angle D is 5.
Therefore, the value of tan D would be.
Hope this helps and I hope you have a marvelous day! :)
As according to the mathematical acronym SOH CAH TOA (Sin Opposite Hypotenuse, Cos Adjacent Hypotenuse, Tan Opposite Adjacent), the correct answer would be the first choice,
The reason behind this is because the tangent value of an angle is always the length value opposite of given angle over the value adjacent (or right next to) the given angle.
In this case, the question is asking for Tan D. The side value opposite of angle D would be 12, and the length value that is adjacent to angle D is 5.
Therefore, the value of tan D would be
Hope this helps and I hope you have a marvelous day! :)
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Answer:
Maximum Profit = 13050
when
The Toy company sells Jordan Size hoops = 7
The Toy company sells Shaq Size hoops = 3
Step-by-step explanation:
Given - The Toy Company sells two types of kids' basketball hoops, Jordan size and Shaq size. A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together. The Company requires the neighborhood to order at least 2 Jordan sizes and at least 3 Shaq sizes. The Toy Company makes a profit of $1,350 on the Jordan size and $1,200 on the Shaq size.
To find - What is the maximum profit they can make given the constraints above?
Proof -
Let us assume that,
The Toy company sells Jordan Size hoops = x
The Toy company sells Shaq Size hoops = y
Now,
Given that, A neighborhood needs no more than 10 Jordan sizes and Shaq sizes all together.
⇒x + y ≤ 10
Now,
Given that, The Company requires the neighborhood to order at least 2 Jordan sizes and at least 3 Shaq sizes.
⇒ x ≥ 2
y ≥ 3
Now,
Given that,
The Toy Company makes a profit of $1,350 on the Jordan size and $1,200 on the Shaq size.
So,
The objective function becomes
Z = 1350x + 1200 y
So,
The Linear Programming Problem (LPP) becomes
Maximize Z = 1350x + 1200 y
Subject to
x + y ≤ 10
x ≥ 2
y ≥ 3
x, y ≥ 0
We will Solve the LPP by Graphical method.
The graph is as follows :
The points on the Boundary are -
A(2, 8)
B(2, 3)
C(7, 3)
So,
Points (x,y) Objective function value ( Z = 1350x + 1200y)
B(2,3) 1350(2) + 1200(3) = 6300
C(7,3) 1350(7) + 1200(3) = 13050
A(2,8) 1350(2) + 1200(8) = 12300
So,
Maximum value = 13050 at point C(7,3)
∴ we get
Maximum Profit = 13050
when
The Toy company sells Jordan Size hoops = x = 7
The Toy company sells Shaq Size hoops = y = 3
