The square root of 36y^3 =

Mathematics

1 answer:

Aleks04 [339]3 years ago

6 0

The square roots of 36y^3 are plus and minus 6y^(3/2) .

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What is the solution 6x-19= 2(x-1) +11

stiv31 [10]

So because of PEMDAS you want to distribute the 2 to the parentheses so you'll get

6x-19=2x-2+11

Then you can just add like terms

6x-19=2x+9

Now you want to get all your variables on one side so you'd add 19 and subtract 2x

4x=28

Now you divide 28 by 4

x = 7

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3 years ago

1. If the domain of a function f(x) is the set {10, 20, 30}. What does the information tell you about f-1(x)?

ziro4ka [17]

PART A (1 in diagram)

Each mapping diagram represents a function because none of the elements in the inputs maps on to two different elements in the outputs.

1. The domain of the given function f(x) is the set {10, 20, 30}.

All we can say about

${f}^{ - 1} (x)$

is that, it has a range of {10, 20, 30}.

This is because the domain of a function becomes the range of its inverse function.

2. If the graph of a function f(x) includes the point (3, 0), then the graph of the inverse function ,

${f}^{ - 1} (x)$

will contain the point (0,3).

Reason:The point on the graph of the inverse function is obtained by reflecting the corresponding point on the graph of the function in the line y=x. We just have to swap the coordinates.

In simple terms the domain of the function becomes the range of the inverse function and vice versa.

3. If the first term in an arithmetic sequence is 2.

Then we have a=2.

If the twelfth term is 211, then

$a + 11d = 211...(1)$