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mart [117]
3 years ago
7

−15x+60≤105 AND14x+11≤−31

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0

Answer:

-15x<=45 and 14x<=-42

x>=45/-15 and x<=-42/14

x>=-3 and x<=-3

so x=-3

Step-by-step explanation:

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A. Factor the polynomial: x^5-4x^3+8x^2-32<br> b. Solve by factoring: 2x^2-3x+1=0
lawyer [7]

Answer:

a. (x^3+8)(x^2-4)

b. x=1 and x=1/2

Step-by-step explanation:

a. (x^3+8)(x^2-4) = x^5-4x^3+8x^2-32 [foil method: first,outside,inside,last]

b. use quadratic formula: -b +/- square root b^2-4ac / 2a

2=a; -3=b; 1=c

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3 + 1 / 4 = 4/4 = 1

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7 0
3 years ago
The number of subscribers to an online magazine is increasing by 34% each year. The function represents the number of subscriber
Anna71 [15]

Answer: A.  The expression  (1.05)^{6t} reveals the approximate rate of increase in the number of subscribers if measured six times a year.

Step-by-step explanation:

Here, The number of subscribers to an online magazine is increasing by 34% each year. The function represents the number of subscribers after t years.

f(t) = 13,000(1.34)^t

where (1.34)^t represents rate of increase in the number of subscriber.

If rate is measured six times a year

then the number of subscriber, f(6t)= 13000(1+0.34/6)^{6t}

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Thus, when we measure increment in six times a year then the rate  rate of increase in the number of subscribers=(1.05)^{6t}

Therefore Option A is correct.

Note: Option B) is incorrect because rate of increase in the number of subscribers if measured three times a year = 13000(1.11)^{3t} ( approx)

Option C) is incorrect because rate of increase in the number of subscribers if measured four times a year =  13000(1.085)^{4t} ( approx)

Option D) is incorrect because rate of increase in the number of subscribers if measured two times a year =  13000(1.17)^{2t} ( approx)

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\bold{FULL SOLUTION:}

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timofeeve [1]

544 cm is the answer

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