Answer and Explanation:
Using Javascript:
test7_11_13(num){
If(num%7===0||num%11===0||num%13===0){
Console.log("yes it is a multiple of 7,11 or 13");
}
else{
Console.log("It is not a multiple of any of the numbers");
}
function(num){
var makeString= num.toString();
var splitString= makeString.split("");
var makeNumber= splitString.map(Number());
var New_number= makeNumber.reduce(function(a, b) {
return a+b};,0)
}
If(New_number%2===0){
Console.log("it's an even number");
}
else{
Console.log("it's an odd number")
}
If(num%2===0||num%3===0||num%5===0||num%7===0||num%11===0){
console.log("it's not a prime number");
}
else{
console.log("it's a prime number");
}
}
From the above we have used javascript if..else statements to test the conditions for each question and output the answer to the console using console.log(). In the last part for prime number, you could also choose to use else if statements(if,else if, else if) to test the value of the num parameter and output if it's a prime number.
Answer:
From the keyboard layout invented by Christopher Lathem Sholes. It is now the most used keyboard layout throughout the world
Answer:
There is a wide application of kinematics; it is also used in astrophysics. In mechanical engineering, robotics, and biomechanics, it is used to describe the motion of the system of the joint parts.
<span>I am definitely sure that sending an employee an email with important criticism represents a problem in message channel. Message channel is one of the ways through which two parties (manager-employee) communicate with each other.</span>
Answer:
The program written in C++ is as follows'
#include<iostream>
using namespace std;
int main()
{
string names[3];
cout<<"Please enter three names: "<<endl;
for (int i = 0; i< 3;i++)
{
cin>>names[i];
}
for (int i = 2; i>= 0;i--)
{
cout<<names[i]<<endl;
}
return 0;
}
Explanation:
This line declares an array for 3 elements
string names[3];
This line prompts user for three names
cout<<"Please enter three names: "<<endl;
This following iteration lets user input the three names
for (int i = 0; i< 3;i++) { cin>>names[i]; }
The following iteration prints the three names in reverse order
for (int i = 2; i>= 0;i--) { cout<<names[i]<<endl; }
