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vivado [14]
3 years ago
6

A disk drive has 2000 cylinders, numbered 0 to 1999. The drive is currently servicing a request at cylinder 783, with the previo

us request at cylinder 707. The queue of pending requests, in FIFO order, is 75, 678, 1623, 247, 248, 1529, 182. What distance, in tracks, must the disk read-write arm move in order to service the requests for each of the following disk scheduling algorithms?
a) FCFS
b) SSTF
c) SCAN
d) LOOK
e) C-SCAN
f) C-LOOK
Computers and Technology
1 answer:
Ket [755]3 years ago
5 0

Answer:

Suppose that a disk drive has 5000 cylinders, numbered 0 to 4999. The drive is currently serving a request at cylinder 143, and the previous request was at cylinder 125. The queue of pending requests, in FIFO order, is

Explanation:

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Write a class that specify the characteristics of a car, like type (sedan, jeep, mini, SUV, etc), gear (auto, manual), maximum s
iVinArrow [24]

Answer:

Answered below

Explanation:

This is written in Kotlin programming language.

//Creating the class Car. The primary //constructor declares car's properties which //are initialized when it's objects are created.

class Car(

val type: String,

val gear: String,

val maxSpeed: Double,

val avgFuelConsumption: Double)

//Creating several objects of car.

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Program MATH_SCORES: Your math instructor gives three tests worth 50 points each. You can drop one of the test scores. The final
Simora [160]

Answer:

import java.util.Scanner;

public class num5 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       //Prompt and receive the three Scores

       int score1;

       int score2;

       int score3;

       do {

           System.out.println("Enter first Score Enter score between 1 -50");

           score1 = in.nextInt();

       } while(score1>50 || score1<0);

       do {

           System.out.println("Enter second Score.The second score must be between 1 -50");

           score2 = in.nextInt();

       } while(score2>50 || score2<0);

       do {

           System.out.println("Enter Third Score Third score must between 1 -50");

           score3 = in.nextInt();

       } while(score3>50 || score3<0);

       //Find the minimum of the three to drop

       int min, min2, max;

       if(score1<score2 && score1<score3){

           min = score1;

           min2 = score2;

           max = score3;

       }

       else if(score2 < score1 && score2<score3){

           min = score2;

           min2 = score1;

           max = score3;

       }

       else{

           min = score3;

           min2 = score1;

           max = score2;

       }

       System.out.println("your entered "+max+", "+min2+" and "+min+" the min is");

       int total = max+min2;

       System.out.println("Total of the two highest is "+total);

       //Finding the grade based on the cut-off points given

       if(total>=90){

           System.out.println("Grade is A");

       }

       else if(total>=80){

           System.out.println("Grade is B");

       }

       else if(total>=70){

           System.out.println("Grade is C");

       }

       else if(total>=60){

           System.out.println("Grade is D");

       }

       else{

           System.out.println("Grade is F");

       }

   }

}

Explanation:

  • Implemented with Java
  • Use the scanner class to receive user input
  • Use a do.....while loop to validate user input for each of the variables. A valid score must be between 0 and 50 while(score>50 || score<0);  
  • Use if and else to find the minimum of the three values and drop
  • Add the two highest numbers
  • use if/else if /else statements to print the corresponding grade
8 0
3 years ago
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