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3 years ago

Describe a situation with two quantities that have a proportional linear relationship.

Mathematics

1 answer:

posledela3 years ago

5 0

Huffing chin chin cfhjbvuknvghjbgy

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If A DEF ~A PMR, then A FDE QA RPM. O True O False

Airida [17]

Answer:

true

Step-by-step explanation:

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2 years ago

Read 2 more answers

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katrin [286]

Given the slope m and a point (a,b) of a line, its equation is given by

$y-b=m(x-a)$

In your case, a = -4, b = 7 and m=1/2, so we have

$y-7=\dfrac{1}{2}(x+4) \iff y=\dfrac{x}{2}+2+7\iff y=\dfrac{x}{2}+9$

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3 years ago

What's 0.003 is 1/10 of what?

zvonat [6]

0.03 you just times it by ten or if its a decimal take away the 0 infront of it

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3 years ago

Find a point on the ellipsoid x2+y2+4z2=36x2+y2+4z2=36 where the tangent plane is perpendicular to the line with parametric equa

Anvisha [2.4K]

Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) : $x^2+y^2+4z^2=36$

Parametric equations:

x=-4t-1

y=2t+1

z=8t+3

Finding the gradient of function

$\nabla f(x,y,z)=\\\nabla f(x,y,z)=$

So, The directions vectors=(-4,2,8)

Now the line is perpendicular to plane when direction vector is parallel to the normal vector of line

$\nablaf(x,y,z)=(2x,2y,8z)=\lambda(-4,2,8)$

So, $2x=-4\lambda$

$\Rightarrow x=-2\lambda$

$2y=2\lambda\\\Rightarrow y=\lambda\\8z=8\lambda\\\Rightarrow z=\lambda$

Substitute the value of x , y and z in the ellipsoid equation

$(2\lambda)^2+(\lambda)^2+4(\lambda)^2=36\\9(\lambda)^2=36\\\lambda^2=4\\\lambda=\pm 2$

With $\lambda = 2$

x=-2(2)=-4

y=2

z=2

With $\lambda =- 2$

x=-2(-2)=4

y=-2

z=-2

Hence a point on the ellipsoid is (-4,2,2) or (4,-2,-2)

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3 years ago

What equation shows the relationship between the profit function, cost function and revenue function?

vlabodo [156]

Profit function - Cost function = Revenue function

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3 years ago