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Shalnov [3]
3 years ago
15

Healthy Gym

Mathematics
2 answers:
ehidna [41]3 years ago
8 0

Answer:

c=2d+5

Step-by-step explanation:

Let

d ------> the number of days

c -----> the cost

we know that

The cost is equal to the number of days multiplied by $2 per day plus the initial fee of $5

The linear equation in slope-intercept form is

c=md+b

where

m is the slope

b is the c-intercept (value of c when the value of d is equal to zero)

in this problem we have

m=$2 per day

b=$5

substitute

c=2d+5

Juliette [100K]3 years ago
3 0

Answer:

c = d + 15

Step-by-step explanation:

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Answer: B and E

Step-by-step explanation:

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Not really getting this can someone plz explain.
Komok [63]

your answer would be b becuase that is 3/6 so thats half and ou would simply it and 1/4 do the same

7 0
3 years ago
The circumference of a circle is 7pi ft. Find its diameter in feet
Mumz [18]

Answer:

The diameter is 7 ft.

Step-by-step explanation:

Circumference= Diameter*pi

5 0
4 years ago
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A photographic negative is 3 cm by 2 cm. A similar print from the negative is 9cm long on its shorter side. What is the length o
lbvjy [14]

Answer:

13.5 cm

Step-by-step explanation:

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3 X 4.5 = 13.5

The new print is 13.5cm by 9cm

5 0
4 years ago
15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>​
Sav [38]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

It looks like we're given

\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

\cos^2t=\dfrac{1+\cos(2t)}2

\sin^2t=\dfrac{1-\cos(2t)}2

so that

\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}

Then we have

\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t

\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}

\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}

where the last reduction follows from dividing through everything by \cos(2t)\cos^2t and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0
3 years ago
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