There will not be any specific name given to that image after translation
<u>Step-by-step explanation:</u>
- Whatever may be the transformation, either it may be rotation, reflection or translation, the size or shape of the image will not change no matter what the condition is and hence the name of that image will also not change and remains constant.
- Thus we can conclude that the name of the image will always tend to remain constant and not changes.
Answer:
r = 3
Step-by-step explanation:
x^2 + 6x + y^2 - 8y = - 16
Take half the linear term and square it.
x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16
Add the squared amounts to the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16
Combine on the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = 9
Represent the 2 quadratics as perfect squares.
(x + 3)^2 + y - 4)^2 = 9
The radius is the square root of 9 which is 3
Answer:
b =0
Step-by-step explanation:
The only value where |b| = -b is when b=0
|0| = -0
0 = 0
Absolute value means non- negative
non-negative = negative
This is only true when we equal zero
Answer:
12.4
Step-by-step explanation:
I.) (5x+3)/4-(2x-4)/3=5
Clear fractions:
3·((5x+3)/4)=15x+9
4·((2x-4)/3)=8x-16
15x+9-(8x-16)=5
15x+9-8x+16=5
Combine like terms:
7x+25=5
7x=-20
x=-20/7
II.) (3/11)·(5/6)-(9/12)·(4/3)+(5/13)·(6/15)
Remember PEMDAS
So first multiply:
3/11·5/6=15/66
9/12·4/3=3/3·1/1=3/3=1
5/13·6/15=1/13·6/3=6/39=2/13
(15/66)-1+(2/13)
Combine:
15/66-1/1=15/66-66/66=-51/66
-51/66+2/3=-51/66+44/66=-7/66
Answer: -7/66 :)
