1
P(V|A) is not 0.95. It is opposite:
P(A|V)=0.95
From the text we can also conclude, that
P(A|∼V)=0.1
P(B|V)=0.9
P(B|∼V)=0.05
P(V)=0.01
P(∼V)=0.99
What you need to calculate and compare is P(V|A) and P(V|B)
P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)
P(V∩A) means, that Joe has a virus and it is detected, so
P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095
P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:
P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085
Answer:
no. because if you divide 4/15 you will get 0.266666.....
2 gross finger puppets; 2 gross bookmarks; 4 gross assorted pencils; 2 gross animal erasers; 2 gross foam craft kits; 2 gross glow in the dark stickers.
This gives 14 gross prizes; 14*144 = 2016.
Expecting 225 guests, with 8 prizes per bag = 225*8 = 1800
This gives enough extra for 27 more bags, in case more people than expected show up.
Answer:
X= - 12/7 i hope it is helpful have a nice day if you want steps i will show you
Step-by-step explanation:
0.2m^3 = 0.0000002 cm^3
