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andrey2020 [161]
3 years ago
13

What rate of interest compounded annually is required to triple an investment in 10 years?

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

The interest rate should be 11.6%.

Step-by-step explanation:

Let us assume that at r% rate of interest compounded annually is required to triple an investment of $P in 10 years.

So, using the formula of compound interest, we can write

3P = P(1 + \frac{r}{100})^{10}

⇒ 3 = (1 + \frac{r}{100})^{10}

⇒ (1 + \frac{r}{100}) = 1.116

⇒ \frac{r}{100} = 0.116

⇒ r = 11.6 %

Therefore, the interest rate should be 11.6%. (Answer)

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As we already have the model that describes the change of the population in Italy in terms of the years that have elapsed, we only have to replace the conditions that are requested in that equation.

Therefore to find the population of Italy in the year 2000 (t = 10 years)  substitute t = 10 in the equation and have:

p = 56.8e^{0.0015*10}\\

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To find the population of Italy in 2008 (t = 18 years)

substitute t = 18 in the equation and have:

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To predict the population in Italy for 2015 and 2020 with this model, we substitute in the equation t = 25 and t = 30

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2 years ago
0.000000452 in scientific notation
Marta_Voda [28]

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Please help me i need to solve for RS
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Answer:

<h2>         RS = 47</h2>

Step-by-step explanation:

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So:

3x+5=\dfrac{2x+15+6x-37}{2}\\\\3x+5=\dfrac{8x-22}{2}\\\\3x+5=4x-11\\^{\qquad-5\qquad-5}\\3x=4x-16\\^{-4x\qquad-4x}\\-x=-16\\^{\div(-1)\quad\div(-1)}\\x=16\\\\RS=2x+15=2\cdot16+15=32+15=47

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What is the slope of the graph?
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(2,3) and (7,6)

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If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e
Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

  • <em>99 is an outlier of pet group</em>
  • <em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

n = 15

The quartiles positions are:

Q_1 = \frac{n + 1}{4}

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Q_3 = Q_1 \times 3

Q_3 = 4th \times 3

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So, we have:

Q_1 = 4th

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From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

Q_1 = 68

Q_3= 79

The lower and upper limits of the outlier are:

L = Q_1 - 1.5 \times (Q_3 - Q_1)

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So, we have:

L = 68 - 1.5 \times (79 - 68)

L = 51.5

U = 79+ 1.5 \times (79 - 68)

U = 95.5

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

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