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andrey2020 [161]
3 years ago
13

What rate of interest compounded annually is required to triple an investment in 10 years?

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

The interest rate should be 11.6%.

Step-by-step explanation:

Let us assume that at r% rate of interest compounded annually is required to triple an investment of $P in 10 years.

So, using the formula of compound interest, we can write

3P = P(1 + \frac{r}{100})^{10}

⇒ 3 = (1 + \frac{r}{100})^{10}

⇒ (1 + \frac{r}{100}) = 1.116

⇒ \frac{r}{100} = 0.116

⇒ r = 11.6 %

Therefore, the interest rate should be 11.6%. (Answer)

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Find the degree of the polynomial: a^3+3a^2−5a
emmainna [20.7K]

Answer:

The degree of the polynomial is 3

Step-by-step explanation:

Given:

a^3+3a^2-5a

To Find:

The degree of the polynomial= ?

Solution:

The degree of the polynomial   is the value of the greatest exponent of any expression (except the constant ) in the polynomial. To find the degree all that you have to do is find the largest exponent in the polynomial

Here in the given polynomial

a^3+3a^2- 5a

The terms are

a^3

3a^2

5a

The term  a^3 has  the largest exponent of  3

Note:  The degree of the polynomial does not depend  on coefficients of the terms

3 0
3 years ago
Find and equation for the line that passes through the points (-6,-4) and (4,4).
Ghella [55]
We have (x-4)/(-6-4) = (y-4)/(-4-4);
(x-4)/(-10) = (y-4)/(-8);
(x-4)/5 = (y-4)/4;
4x-16 = 5y-20;
4x - 5y + 4 = 0;
5 0
3 years ago
Read 2 more answers
Simplify each radical
const2013 [10]

Answer:

AECG

Step-by-step explanation:

1

sqrt(49) = 7

sqrt(a^2) = a

sqrt(b^2) = b

For every two variables you can take one out from under the root sign and thorough the other one away.

Answer: E

2

sqrt(36) = 6

sqrt(a^2) = a  See comment for 1.

b must be left where it is. There is only 1 of them.

6asqrt(b)

Answer: A

3. sqrt(25) = 5

sqrt(b^2) = b

a must be left alone.  There's only 1 of them.

5b sqrt(a)

answer: C

4

sqrt(81 a b)

sqrt(81) = 9

The variables must be left alone. There's only1 of them

9 sqrt(ab)

Answer G

8 0
2 years ago
I NEED HELP QUICKLY!!! What is the sum of the first 140 positive multiples of 3?
garri49 [273]

Answer:

C

Step-by-step explanation:

The multiples of 3 are

3, 6, 9, 12, 15, ...........

The terms form an arithmetic sequence with common difference of 3.

The sum to n terms is

S_{n} = \frac{n}{2} [2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 3 and d = 3, thus

S_{140} = \frac{140}{2} [ (2 × 3) + (139 × 3) ]

                            = 70(6 + 417) ] = 70 × 423 = 29610 → C

5 0
3 years ago
The table shows information about some children.
Sindrei [870]

Answer:

P(Age\ 12) = \frac{2}{3}

Step-by-step explanation:

Given

        Age 11    Age 12    Total  

Girls   3             5              8

Boys   1             3             4

Required

P(Age\ 12)

The number of aged 12 children is:

Age\ 12 = 5 + 3

Age\ 12 = 8

The total number of children is:

Total=8+4

Total = 12

So, we have:

P(Age\ 12) = \frac{Age\ 12}{Total}

P(Age\ 12) = \frac{8}{12}

Simplify

P(Age\ 12) = \frac{2}{3}

3 0
3 years ago
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