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andrey2020 [161]
3 years ago
13

What rate of interest compounded annually is required to triple an investment in 10 years?

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

The interest rate should be 11.6%.

Step-by-step explanation:

Let us assume that at r% rate of interest compounded annually is required to triple an investment of $P in 10 years.

So, using the formula of compound interest, we can write

3P = P(1 + \frac{r}{100})^{10}

⇒ 3 = (1 + \frac{r}{100})^{10}

⇒ (1 + \frac{r}{100}) = 1.116

⇒ \frac{r}{100} = 0.116

⇒ r = 11.6 %

Therefore, the interest rate should be 11.6%. (Answer)

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. The total area of a rectangular mural has been extended by x feet. The expression to represent the area is 5.5(7.5 + x). Rewri
alexandr1967 [171]

Answer and Step-by-step explanation: <u>Distributive</u> <u>Property</u> describes how to solve expressions like a(b +c). According to the property, multiplying the sum of two or more numbers by a number will result in the same as multiplying each number and then add the products. For example:

                 11(2 + 4)

11(6) = 66                 22 + 44 = 66

So, for the expression that represents the area:

5.5(7.5 + x) = 41.25 + 5.5x

As the expression has non-numerical terms, the distributive property will be multiply each term and then add the products.

The expressio for area of a rectangular mural is 41.25 + 5.5x.

7 0
3 years ago
Which shows the expressions in the order they would appear on a number line from least to greatest?
Ganezh [65]
2^3 = 8
11/9 = 1.22
sqrt 5 = 2.24
sqrt 20 = 4.47
sqrt 11 = 3.32

least to greatest : 11/9, sqrt 5 , sqrt 11 , sqrt 20, 2^3
7 0
3 years ago
(1 - cosx) (1 + 1/cosx) = sinxtanx
Nataly [62]

Answer:

cos x ≠ 0 ⇔ x ≠ \frac{pi}{2}+k.pi ; k ∈ N

(1-cosx)(1+\frac{1}{cosx})=sinx.tanx\\\\(1-cosx)(\frac{cosx+1}{cosx})=sinx.\frac{sinx}{cosx}\\\\ \frac{1-cos^{2} x}{cosx} =\frac{sin^{2}x }{cosx}\\\\=>1-cos^{2}x=sin^{2}x

<=> cos²x + sin²x = 1

⇔ 1 = 1

=> x =  { R \ (pi/2 + k.pi); k ∈ N}

Step-by-step explanation:

5 0
3 years ago
Write an inequality involving the variable x that describes the set of numbers graphed.
Anna [14]
Since it does not include 0 in the inequality, nor does it include any numbers below 0, it must be \boxed{x\ \textgreater \ 0}. 
3 0
3 years ago
Please answer this question now
shusha [124]

Hi there! :)

Answer:

\huge\boxed{V = 359.01 mm^{3} }

Use the formula V = 1/3(bh) to solve for the volume of the cone where b = πr² where π ≈ 3.14:

Find the area of the base:

b = π(7)²

b = 49π

b = 153.86 mm²

Find the volume:

V = 1/3(153.86 · 7)

V = 1/3(1077.02)

V = 359.006 ≈ 359.01 mm³.

4 0
3 years ago
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