Question

A round- trip car ride took 12 hours. The first half of the trip took 7 hours at a rate of 45 miles per hour. What was the average rate of speed on the return trip ?

Answer 1

Answer:

63 mph

Step-by-step explanation:

Given:

• Trip duration = 12 hours
• First half duration = 7 hours
• First half speed = 45 mph

To find:

• Return speed = ?

Solution:

• One way distance = 7*45 = 315 miles
• Time on return = 12 - 7 = 5 hours
• Average speed on return trip= 315 / 5 = 63 mph

Answer 2

Step-by-step explanation:

Total time taken by car to travel :12hrs

1st half:7hrs (which is to go)

Avg speed by car in 1st half :45mph

To find the avg speed at return time is

12-7 =5hrs (we did this to find time taken to return from or (-) total time of journey )

Total dist traveled to go will be

7x45=315mph therefore 315 m was covered to go.

Distance on return triip would be same as 315 because he is returning back along the same path

So formula for speed is s=d/t

On substitute

S=315/5. = 63mph

There fore the avg speed on return trip will be 63mph.

To verify,

We know total dist traveled (315) m

So 63x 5=315 therefore prooved 63 mph was the avg speed

Note*: in above context m means miles and not meters

Please mark it as brainliest!

Thanks.