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olchik [2.2K]
3 years ago
7

Jan wants to protect the wooden box in question 4a by painting varnish on all of the outside surfaces, including the bottom. Wil

l a container of varnish that covers 275 square inches be enough to protect the outside surfaces of the box?
Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

As this question is incomplete, but we will try to solve this question by adding our own data to understand the concept of the problem.

Explanation is given below

Step-by-step explanation:

As this question is incomplete, but we will try to solve this question by adding our own data to understand the concept of the problem.

In order to answer this question we need to have the dimensions of the box.

Let's suppose there are 6 outside surfaces of the box and are equal in dimension including the bottom side which Jan wants to varnish.

So,

Let's suppose,

Surface area of the cube = 6a^{2}

Here, Surface area = 275 square inch

Surface area of the cube = 6a^{2} = 275 square inch

a^{2} = 275/6 = 45.833

a = \sqrt{45.833}

a = 6.77 inches

Now, for the amount of the varnish, we need the spreading rate of the varnish to be used on the box,

Let's suppose it is = 11 square incher per litre.

So,

Required Varnish = Surface area / Spreading rate

Required varnish = 275 / 11

Required varnish = 25 liters

If the 1 container of varnish contains 25 liters then it will be sufficient to protest the outside surfaces of the box.

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Since 23 is much, much closer to the square of 5 than the square of 4, we can assume that the value √23 will be closer to 5 on the number line than 4.

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