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lana66690 [7]
3 years ago
9

Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for sev

eral seconds. The player began counting at 0 seconds even though the video had already played 190 frames The video plays 252525 frames per second. How many frames had the video already played when the time was equal to -3 3/5
Mathematics
1 answer:
Bess [88]3 years ago
3 0

Answer:

105 frames

Step-by-step explanation:

Given that 25 frames are played per second

25 frames= 1 sec

The video already played 3 and 2/5 seconds before the player started to count 0

Write 3 and 2/5 seconds as an improper fraction

=(5*3)+2 / 5 = 17/5 seconds

Multiply by 25 frames

17/5 *25 =85 frames

So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.

190-85=105 frames.

Step-by-step explanation:

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goblinko [34]
8p² - 16p = 10

8p² - 16p - 10 = 0      Divide through by 2

4p² - 8p - 5 = 0

Multiply first and last coefficients:  4*-5 = -20

We look for two numbers that multiply to give -20, and add to give -8

Those two numbers are 2 and -10.

Check:   2*-10 = -20         2 + -10 = -8

We replace the middle term of -8p in the quadratic expression with 2p -10p


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4p² + 2p - 10p - 5 = 0     

2p(2p + 1) - 5(2p + 1) = 0

(2p + 1)(2p - 5) = 0

2p + 1 = 0    or   2p + 5 = 0

2p = 0 -1              2p = 0 - 5

2p = -1                    2p = -5

p = -1/2                    p = -5/2

The solutions are p = -1/2  or  -5/2
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