To find the midpoint, Add the two X coordinates together then divde by two and then to the same with the Y coordinates:
X = -4 + 2 = -2 / 2 = -1
Y = 6+7 = 13/2
Midpoint = (-1,13/2)
Answer:
x = 12
Step-by-step explanation:
We have a right triangle with hypotenuse 10 and the height 8. Either the one on the left or the one on the right
We can find the base using the Pythagorean theorem
a^2 + b^2 = c^2
a^2 +8^2 = 10^2
a^2 +64 = 100
Subtract 64 from each side
a^2 = 100 -64
a^2 = 36
Take the square root of each side
a = 6
Now a is 1/2 of the total base of the big triangle. It is identical since the triangles are equal
x = 2 * a
x = 2*6 = 12
Answer:
(5 × 10^3) + (3 × 10^2) + (2 × 10^1) + (5 × 10^0) = 5,325
Step-by-step explanation:
For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)
For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600
Sum of first 120 positive integers = s + s + 3600 = 2s + 3600
Answer:
Step-by-step explanation:
It is given that triangle AOC intersects a circle with center O, side AO is 10 inches and the diameter of the circle is 12 inches, thus
OC is the radius of the circle and is equal to 
.
Now, From ΔAOC, using the Pythagoras theorem, we get
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