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Delicious77 [7]
3 years ago
6

What is the greatest perimeter of a rectangle with an area of 39 ft.²

Mathematics
1 answer:
Margaret [11]3 years ago
4 0
32 because if you do 13×3, it ia 39. Since it is a rectangle, you do 13+13=26 then 3+3=6. The 26+6=32
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Customers can pick their own pumpkins at the great pumpkin patch. They pay 4$ to enter the patch and 3$ per pound for the pumpki
klasskru [66]

Given, Customers pay $4 to enter the pumpkin patch.

And also given, customers pay $3 per pound for the pumpkins.

Given, $y be the total cost and there are x pounds of pumpkins.

The cost for pumpkin per pound = $3.

Therefore, the cost for x pound pumpkins = $(3x)

As the total cost includes the payment for entering the patch also,

So the total cost y = 3x + 4

We have got the required equation.

The equation to model the total cost is y = 3x+4.

5 0
3 years ago
What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
andre [41]

Answer:

The perimeter is 38.25 units

Step-by-step explanation:

The perimeter of the tra-pezoid is the distance around it.

The length of the bases can be found using the absolute value method.

|RS|=|20-14|=6 units.

|TQ|=|22-8|=14

Recall the distance formula;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We use the distance to find the non parallel sides.

|ST|=\sqrt{(20-22)^2+(16-8)^2} =8.25 units.

and

|QR|=\sqrt{(8-14)^2+(16-8)^2} =10 units.

The perimeter of the tra-pezoid is

=14+10+6+8.25=38.25

7 0
3 years ago
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I could use some help with this question?
slega [8]

Answer:

d

Step-by-step explanation:

if I divide the units of the scaled rectangle by the original you will get

18 \div 9 = 2 \\ 6 \div 3 = 2

3 0
3 years ago
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Exercise 3.5. For each of the following functions determine the inverse image of T = {x ∈ R : 0 ≤ [x^2 − 25}.
masya89 [10]

a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

b. The inverse image of g(x) is g^{-1}(x) = e^{x}

c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

<h3 /><h3>The domain of T</h3>

Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0

⇒ x² ≥ 25

⇒ x ≥ ±5

⇒ -5 ≤ x ≤ 5.

<h3>Inverse image of f(x)</h3>

The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

f : R → R defined by f(x) = 3x³

Let f(x) = y.

So, y = 3x³

Dividing through by 3, we have

y/3 = x³

Taking cube root of both sides, we have

x = ∛(y/3)

Replacing y with x we have

y = ∛(x/3)

Replacing y with f⁻¹(x), we have

So,  the inverse image of f(x) is f⁻¹(x) = ∛(x/3)

<h3>Inverse image of g(x)</h3>

The inverse image of g(x) is g^{-1}(x) = e^{x}

g : R+ → R defined by g(x) = ln(x).

Let g(x) = y

y =  ln(x)

Taking exponents of both sides, we have

e^{y} = e^{lnx} \\e^{y} = x

Replacing x with y, we have

y = e^{x}

Replacing y with g⁻¹(x), we have

So, the inverse image of g(x) is g^{-1}(x) = e^{x}

<h3>Inverse image of h(x)</h3>

The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

h : R → R defined by h(x) = x − 9

Let y = h(x)

y = x - 9

Adding 9 to both sides, we have

y + 9 = x

Replacing x with y, we have

x + 9 = y

Replacing y with h⁻¹(x), we have

So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

Learn more about inverse image of a function here:

brainly.com/question/9028678

5 0
2 years ago
Bill paid $2.49 for 5 pounds of rice. What could be cost of 9 pounds
Nadya [2.5K]

Answer:

\boxed{\sf Cost \ of \ 9 \ pounds \ rice =\$ 4.482}

Given:

5 pounds rice cost $2.49

To Find:

Cost of 9 pounds rice

Step-by-step explanation:

5 pounds rice cost $2.49

1 pound rice will cost $ \sf \frac{2.49}{5}

So,

9 pounds rice cost = 1 pound rice cost × 9

= $ \sf \frac{2.49}{5} \times 9

= $0.498 × 9

= $4.482

3 0
3 years ago
Read 2 more answers
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