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3 years ago

Solve for x. x^2+ 12x+ 36 = 0 X=

Mathematics

1 answer:

Valentin [98]3 years ago

4 0

Answer:

-6 = x

Step-by-step explanation:

x² + 12x + 36 → [x + 6]² = 0

-6 = x

I am joyous to assist you anytime.

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Answer:

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Step-by-step explanation:

m= (y2 - y1) / (x2 - x1)

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4 years ago

H=7+44t-16^2

zalisa [80]

Answer:

When t=2.1753 & t=.5746 , h=27

Don't worry, I got you. Also, my calculator does too.

We set h equal to 27, because we want the height to be 27 when we solve for t.

That leaves us with:

27 = 7 + 44t - 16t^2

Simplify like terms,

20 = 44t - 16t^2

Move 20 onto the right side, so we can use quadratic equation

44t - 16t^2 - 20 = 0 --> -16t^2 + 44t - 20

Using quadratic, you get

t=2.1753 & t=.5746

poster confirmed : "It’s t=2.18 and t=0.57"

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2 years ago

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3 years ago

Solve this equation using elimination distribution or substitutionX^2=11x-10

Tema [17]

Answer:

it either x = 10 or x = 1

Step-by-step explanation:

8 0

3 years ago

The hypotenuse of a right angled triangle is 2√13 cm . If the smaller side is increased by 2 cm and the larger side is increased

White raven [17]

Statement:

The hypotenuse of a right angled triangle is 2√13 cm. If the smaller side is increased by 2 cm and the larger side is increased by 3 cm, the new hypotenuse will be √117 cm.

To find out:

The length of the larger side of the right angled triangle.

Solution:

Let us consider x as the smaller side and y as the larger side.

Then, in the right angled triangle,

x² + y² = (2√13)² ...(I) [By Pythagoras Theorem]

Now, if the smaller side is increased by 2 cm, then the smaller side will be (x + 2).

And if the larger side is increased by 3 cm, then the larger side will be (y + 3).

Then, in the new right angled triangle,

(x + 2)² + (y + 3)² = (√117)² [By Pythagoras Theorem]

or, x² + 2 × 2 × x + 2² + y² + 2 × 3 × y + 3² = (√117)²

or, x² + 4x + 4 + y² + 6y + 9 = (√117)²

or, x² + y² + 4x + 6y + 13 = (√117)²

Now, put the value of x² + y² from equation (I),

or, (2√13)² + 4x + 6y + 13 = (√117)²

or, (2 × 2 × √13 × √13) + 4x + 6y + 13 = (√117 × √117)

or, 52 + 4x + 6y + 13 = 117

or, 4x + 6y = 117 - 52 - 13

or, 4x + 6y = 52

or, 4x = 52 - 6y

or, x = $\frac {(52 - 6y)}{4}$ ...(II)

Now, put the value of x of equation (II) in (I),

x² + y² = (2√13)²

or, $\frac {(2704-624y +36y²)}{16}$ + y² = 52

or, $\frac {(2704-624y +36y² + 16y²)}{16}$ = 52

or, 52y²-624y + 2704 = 52 × 16

or, 52y² - 624y + 2704 - 832 = 0

or, 52y² - 624y + 1872 = 0

or, 52(y² - 12y + 36) = 0

or, y²-12y +36 = 0 ÷ 52

or, y²-12y +36 = 0

or, (y)² - 2 × 6 × y + (6)² = 0

or, (y - 6)² = 0

or, y - 6=0

or, y = 6

We have taken y as the length of the larger side of the right angled triangle.

So, the length of the larger side is 6 cm.

Answer:

6 cm

Hope you could understand.

If you have any query, feel free to ask.

6 0

3 years ago