Amount =$48003.20
Step-by-step explanation:
Here apply the compound interest formula;

where;
P=Principal amount invested = $37500
r=rate of interest as a decimal, 2.5% =0.025
n=number of compounding per year=1
t=time period the amount in invested=10
In our case, the amount after investing will be;

Interest earned after the period= $48003.20-$37500 =$10503.20
Learn More
Compound Interest formula application: brainly.com/question/7014337
Keywords: inherit, sum, money, interest
#LearnwithBrainly
Answer:
2y(7x + 4z)
Step-by-step explanation:
Consider the common factors of both terms
The gcf of 14 and 8 is 2
The gcf of xy and yz is y
Thus the gcf of both terms is 2y, thus
14xy + 8yz
= 2y(7x + 4z)
(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>
We are required to find the total sum of money given the fraction
The total sum of money is $9
let
<em>Total sum of money</em> = x
<em>8 1/3 of x = $75</em>
8 1/3 × x = $75
25/3 × x = 75
25/3x = 75
Divide both sides by 25/3
x = 75 ÷ 25/3
x = 75 × 3/25
x = (75 × 3) / 25
x = 225 / 25
x = 9
Therefore, the total sum of money is $9
Read more:
brainly.com/question/9017965
This is the answer its easy just simplify the inequality